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vovikov84 [41]
3 years ago
10

HELP PLEASE ASAP! I really need it!

Mathematics
1 answer:
Tomtit [17]3 years ago
6 0

- 4\sqrt[]{x - 3} = 12 \\  \sqrt{x - 3}   =   \frac{12}{ - 4}  \\  \  \sqrt{x - 3}  =  - 3 \\ x - 3 =  { (- 3)}^{2}  \\ x = 12
the answer is D
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Norma-Jean [14]
X = 2

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One side of the larger triangle is x inches plus an additional 8 inches, which can be written as (x+8)

To get the perimeter of the larger square, multiply the expression (x+8) by 4. The question states the larger square’s perimeter is 40 inches.

You end up with this equation: 4(x + 8) = 40

To solve first distribution 4 into (x + 8).
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x = 2 inches

So the side length of the original square is 2 inches. To check your work, go back and plug x = 2 into the original equation. 8 in + 2 in = 10 inches, and 10 inches x 4 = 40 inches, so x = 2 is the solution
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2 years ago
The point P on the circle x2 + y2 = r2 that is also on the terminal side of an angle θ in standard position is given. Find the i
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3 years ago
Jenny uses a roller to paint a wall. The roller has a radius of 1.75 inches and a height of 10 inches. In two rolls, what is the
Katen [24]

Answer:

The area of the wall that she will paint in two rolls is <u>219.8 inches²</u>.

Step-by-step explanation:

Given:

Jenny uses a roller to paint a wall. The roller has a radius of 1.75 inches and a height of 10 inches.

Now, to find the area of the wall that she will paint in two rolls.

So, we find the lateral surface area of roller.

Radius (r) = 1.75 inches.

Height (h) = 10 inches.

So, to get the lateral surface area we put formula:

A_{L} =2\pi rh

A_L=2\times 3.14\times 1.75\times 10

A_L=109.9\ inches^2.

Thus, the lateral surface area of the roller = 109.9 inches².

Now, to get the area of wall that she will paint in two rolls we multiply 2 by the lateral surface area of the roller:

109.9\times 2\\\\=219.8\ inches^2.

Therefore, the area of the wall that she will paint in two rolls is 219.8 inches².

3 0
3 years ago
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An equation with a difference of 6 would be 12-6=6
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