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tigry1 [53]
3 years ago
11

How do you dilate by a scale factor?

Mathematics
2 answers:
nydimaria [60]3 years ago
8 0
Because the scale factor is 3 you would multiply it by 10 and then 6
r-ruslan [8.4K]3 years ago
7 0

multiply the original number to get the new ones

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Gnoma [55]

Answer:

the answer is (x,y) (1,2)

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Suppose you roll one die. Find the probability of rolling an odd number
zepelin [54]
If it's a six sided dice, then it would be 1 out of 3. 

I hope that helped :)
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Noelle stands at the edge of a cliff and drops a rock. The height of the rock is given by the function f(x)-4.9x2 + 15, where c
Oxana [17]
A graphing calculator shows the rocks are at the same height 1.5 seconds after they are released.

That height is 3.975 meters.

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f(x) = g(x)
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15 = 10x . . . . . . . . . . . . . . . . . . add 4.9x^2
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3 0
4 years ago
Directions: Select the correct answer from each drop-down menu.Sandy's orchard has only apple trees and pear trees and she is wa
valentina_108 [34]
First lets get the ratio for the avocado and pear trees and work from there
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Since we know the total Avocado trees is 18 we can find out how much to multiply the ratio by dividing the total number of trees(18) by the Avocado portion of the ratio (2) 18/2 = 9. 

This means to get the total number of pear trees we need to also multiply the pear side of the ratio (5) by 9.  5*9 = 45 pear trees

Now that we know the pear trees we do the same thing with the apple and pear trees to figure out the total apple trees.  The ratio of apple to pear trees is 4:3.

Since we know the total number of pear trees is 45 we divide that by the pear side of the ratio (3) to get our multiplier.  45/3=15. 

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3 0
3 years ago
An object is thrown upward from the top of a 48-foot building with an initial velocity of 32 feetquadratic equation h = - 16t^2+
Alex17521 [72]

SOLUTION

The object would hit the ground at the root of the equation, that is where h = 0

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\begin{gathered} h=-16t^2+32t+48=0 \\ -16t^2+32t+48=0 \\ 16t^2-32t-48=0 \\ divide\text{ through by 16} \\ t^2-2t-3=0 \end{gathered}

Solving the quadratic equation, we have

\begin{gathered} t^2-3t+t-3=0 \\ t(t-3)+1(t-3)=0 \\ (t-3)(t+1)=0 \\ t=3,\text{ or} \\ t=-1 \end{gathered}

So we ignore -1 as time cannot be negative.

Hence the object hit the ground in 3 seconds

3 0
1 year ago
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