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diamong [38]
3 years ago
13

Practice

Mathematics
1 answer:
Mrrafil [7]3 years ago
3 0

Answer:

1. -5y + 2y = -3y

2. -8r - 16 + 6r - 12

3. -8r - -16 + 6r - 12

4. -8r - -16 + 6r - 12

5. 2m +13

Step-by-step explanation:

why is there 2 of the same

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On the last three physics exams a student scored 89, 87, and 92. What score must the student earn on the next exam to have an av
OlgaM077 [116]

Answer:

For the average to be above 90, the marks in the fourth paper should be MORE THAN 92.

Step-by-step explanation:

The score of students in last 3 exams =  89 , 87 and 92

Let us assume the marks scored by the student in last exam = k

The average of marks should be above 90.

Now, \textrm{The average of total marks}  = \frac{\textrm{Sum of all marks obtained in 4 papers}}{\textrm{ 4 papers }}

Sum of all 4 paper's marks =  89 + 87 + 92 + k = 268 + k

Also, 90 <  Average

\implies 90 < \frac{268 + k}{4}\\ or, 360 < 268 + k\\\implies  360 - 268 < k\\or,  k >  92

Hence,for the average to be above 90, the marks in the fourth paper should be MORE THAN 92.

4 0
4 years ago
What is the sum? StartFraction 3 Over x squared minus 9 EndFraction + StartFraction 5 Over x + 3 EndFraction
Karolina [17]

Answer:

The answer is:

\frac{5 x - 12}{(x + 3)(x - 3)}

Step-by-step explanation:

\frac{3}{x ^{2}  - 9}  +  \frac{5}{x + 3}

First, we have to make the denorminator same by multiplying:

\frac{3}{(x + 3)(x - 3)}  +  \frac{5}{x + 3}

\frac{3}{(x + 3)(x - 3)}  +  \frac{5(x - 3)}{(x + 3)(x - 3)}

Then, we can add up everything together:

\frac{3 + 5x - 15}{(x + 3(x - 3)}

\frac{5x - 12}{(x + 3)(x - 3)}

(Sorry if being messy)

8 0
3 years ago
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