Step-by-step explanation:
This is a probability related problem.
Probability is the likelihood of an event to occur;
Pr = 
The sample space here is from 1 to 25 which is 25
A.
Pr of a card marked 8; we have just 1 possible outcome;
Pr(8) = 
B.
Pr of drawing a card that is a multiple of 5;
Multiples of 5 = 5, 10, 15 and 25
Pr (multiples of 5) = 
C.
Pr of drawing a card with odd numbers:
Number of odd numbers between 1 and 25 = 13
Pr(odd numbers) = 
D.
Pr of drawing a number with square number on it;
Square numbers between 1 and 25 = 1, 4, 9, 16 and 25
Pr(square numbers) = 
= 
Answer:
Step-by-step explanation:
Median: 73.5
Note that there's a strict order here -> 2 close friends, then 1 non-close friend.
So, picking in order:
probability of picking the first close friend: 4/10
probability of picking the second close friend: 3/9
probability of picking the first non-close friend: 6/8
So, we get 4/10 * 3/9 * 6/8 = 1/10.
You're given two points for f(t) and g(t) each. Two points, (x1,y1), and (x2,y2). In this case, x1 is always x1=0, since the time t starts counting at the earliest year given.
We know the form y=mx+b. m can be found a la (y2-y1)/(x2-x1), but remember x1 is 0. b can be found at f(0) or g(0), which we're already given; y1 for both cases.
I'm sorry, but I'm not giving a direct answer. Knowing the method, and being careful with calculations, should be more than sufficient.<span>it would be 22395-20808/5=317.4 f(t)
26508-26155/5= 70.6
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