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klio [65]
2 years ago
5

What is the 308th term of the sequence 11,12.5,14,15.5,17...

Mathematics
1 answer:
Alecsey [184]2 years ago
6 0

\huge\boxed{471.5}

The formula for an arithmetic sequence is as follows:

a_n=a_1+(n-1)d

In this formula, a_n represents the nth term of the sequence and d represents the common difference between each term.

Plug in the known values.

a_{308}=11+(308-1)1.5

Subtract.

a_{308}=11+307*1.5

Multiply.

a_{308}=11+460.5

Add.

a_{308}=\boxed{471.5}

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Step-by-step explanation:


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3 years ago
An internet start-up predicts its revenue by a straight-line method with a slope of $7000 per month. In its 6 th month it had re
Margarita [4]
Given that the method of revenue calculation is straight line method, the equation modeling this will be given by:
y=mx+c
where:
m=slope
x=time
c=initial value.
 from our question:
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y(x)=R(t)
hence the formula after the sixth month will be:
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5 0
3 years ago
Use the result (a+b)²=a²+2ab+b² to find the value of 49²+98+1
Leto [7]

Answer:

2500

Step-by-step explanation:

a² + 2ab + b²

49² + 98 + 1

Comparing terms

a²= 49²

a= 49

2ab = 98

2× 49 × b = 98

98b = 98

b= 98/98

b = 1

or

b²= 1

b=√1

b= 1

a=49 and b= 1

Hence (a+b)²= (49+1)²

50²= 2500

5 0
2 years ago
Jessica Reads a story about a turtle that swam 16 feet in 24 seconds. She assumes that the time that it takes the turtle to swim
Zigmanuir [339]

Answer:

Time (secs) => distance (ft)

1 => ⅔

15 => 10

24 => 16

45 => 30

Step-by-step explanation:

Equation to represent this proportional relationship is d = tk, where,

t = time

d = distance

k = constant of proportionality

To complete the table, let's find k given that the turtles swarm 16 ft (d) in 24 secs (t).

Substitute d = 16, t = 24 into the equation.

d = tk

16 = 24k

\frac{16}{24} = k (division property of equality)

\frac{2}{3} = k

Let's complete the table by substituting the value of k and the other given value of t or d, as the case may be:

For 1 sec, let's find distance (d):

d = tk

d = 1*\frac{2}{3}

d = ⅔ ft

For 10 ft, let's find the time (t) taken:

d = tk

10 = t*\frac{2}{3}

Multiply both sides by 3

10*3 = t*\frac{2}{3}*3

30 = t*2

Divide both sides by 2

\frac{30}{2} = \frac{t*2}{2}

15 = t

t = 15 secs

For 45 secs, let's find distance (d):

d = tk

d = 45*\frac{2}{3} = 15*2

d = 30 ft

5 0
3 years ago
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