D = rt. The first car's rate is r, and the other one, going faster, is r + 12. The time they travel is 2 hours. Since one is going faster than the other, he has gotten farther. But, regardless of that, the distance between them is 232. So the distance the first one travels, r*t, which 2r, plus the distance the second one travels, 2(r+12) = 232. 2r + 2r + 24 = 232. Solve for r. 4r = 208 and r = 52. The slower one goes 52 and the faster one goes 64
Answer:
D.) 12
Step-by-step explanation:
16x - 3(4x + 5) = 2x + 9
16x - 12x - 15 = 2x + 9
4x - 2x = 15 + 9
2x = 24
2x/2 = 24/2
x = 12
Check:
16x - 3(4x + 5) = 2x + 9
16(12) - 3(4(12) + 5) = 2(12) + 9
192 - 3(48 + 5) = 2(12) + 9
192 - 3(53) = 24 + 9
192 - 159 = 33
33 = 33
4x + 8 = -12 is the equation for this statement
Answer:
who is that? Maybe i know this person...
Step-by-step explanation:
Answer:
x = - 71
Step-by-step explanation:
x - 12 = - 83
+12 +12 (adding 12 to both sides)
x = - 71
