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3 years ago

What aldol product is formed when two molecules of butanal react together in the presence of base?

Chemistry

1 answer:

Ainat [17]3 years ago

4 0

It is an example of Self Condensation reaction as both the nucleophile and the electrophile are the same compounds. When Butanal is reacted with base, the hydrogen at alpha position is abstracted due to its mild acidity and enolate is formed. Enolate attacks second Butanal molecule and forms a compound containing both Hydroxyl group and carbonyl group (Beta hydroxy aldehyde). Reaction is shown below and the name of product is specified below its structure,

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The following information is to be used for the next 2 questions. In order to analyze for Mg and Ca, a 24-hour urine sample was

Ainat [17]

Answer:

Explanation:

From the given information:

The concentration of metal ions are:

$[Ca^{2+}]= \dfrac{0.003474 \ M \times 20.49 \ mL}{10.0 \ mL}$

$[Ca^{2+}]=0.007118 \ M$

$[Mg^2+] = \dfrac{0.003474 \ M\times (26.23 - 20.49 )mL}{10.0 \ mL}$

$=0.001994 \ M$

Mass of Ca²⁺ in 2.00 L urine sample is:

$= 2.00 L \times 0.001994 \dfrac{mol}{L} \times \dfrac{40.08 \ g}{1 \ mol}$

= 0.1598 g

Mass of Ca²⁺ = 159.0 mg

Mass of Mg²⁺ in 2.00 L urine sample is:

$= 2.00 L \times 0.007118 \dfrac{mol}{L} \times \dfrac{24.31 \ g}{1 \ mol}$

= 0.3461 g

Mass of Mg²⁺ = 346.1 mg

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