The balanced equation for the above reaction is 2K₃PO₄ + 3NiCl₂ ---> 6KCl + Ni₃(PO₄)₂ stoichiometry of K₃PO₄ to NiCl₂ is 2:3 the number of NiCl₂ moles reacted - 0.0110 mol/L x 0.154 L = 1.69 x 10⁻³ mol if 3 mol of NiCl₂ reacts with - 2 mol of K₃PO₄ then 1.69 x 10⁻³ mol of NiCl₂ reacts with - 2/3 x 1.69 x 10⁻³ = 1.13 x 10⁻³ mol of K₃PO₄ molarity of K₃PO₄ solution given - 0.205 M there are 0.205 mol in 1 L therefore 1.13 x 10⁻³ mol are in - 1.13 x 10⁻³ mol / 0.205 mol/L = 5.51 mL volume of K₃PO₄ required - 5.51 mL
