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Alex73 [517]
3 years ago
10

What volume of 0.205 m k3po4 solution is necessary to completely react with 154 ml of 0.0110 m nicl2? 1.65 l?

Chemistry
1 answer:
sasho [114]3 years ago
3 0
The balanced equation for the above reaction is 
2K₃PO₄   + 3NiCl₂  ---> 6KCl + Ni₃(PO₄)₂
stoichiometry of K₃PO₄  to NiCl₂ is 2:3
the number of NiCl₂ moles reacted - 0.0110 mol/L x 0.154 L = 1.69 x 10⁻³ mol
if 3 mol of NiCl₂ reacts with - 2 mol of K₃PO₄ 
then 1.69 x 10⁻³ mol of NiCl₂ reacts with - 2/3 x 1.69 x 10⁻³  = 1.13 x 10⁻³ mol of K₃PO₄
molarity of K₃PO₄ solution given - 0.205 M
there are 0.205 mol in 1 L
therefore 1.13 x 10⁻³ mol are in - 1.13 x 10⁻³ mol / 0.205 mol/L = 5.51 mL
volume of K₃PO₄ required - 5.51 mL
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Molarity is the molar concentration of the solute dissolved in a volume of a solution. The molarity of the solution prepared by dissolving barium chloride will be 0.085 M.

<h3>What is molarity?</h3>

Molarity is the ratio of the moles of the solute to that of the volume of the solution in Liters. It can be given as,

\rm Molarity = \dfrac{moles}{Volume}

Here, moles of the barium chloride can be given by the mass and the molar mass and volume is given as 0.450 L.

Substituting values in the equation:

\begin{aligned}\rm Molarity &= \rm \dfrac{mass}{Molar \;mass\times Volume}\\\\&= \dfrac{8}{208.23\times 0.450}\\\\&= 0.085\;\rm M\end{aligned}

Therefore, 0.085 M barium chloride is the molar concentration.

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