Answer:
Molarity NaOH = 0.85M (2 sig figs)
Explanation:
48.0ml(0.220M H₂SO₄) + 25ml(Xmolar NaOH)H₂SO₄ + 2NaOH => Na₂SO₄ + 2H₂O
2(molarity x volume) H₂SO₄ = (molarity x volume) NaOH
2(0.220M x 48.0ml) = 25.0ml x Molarity NaOH
Molarity NaOH = 2(0.220M x 48.0ml)/25.0ml = 0.8448M ≅ 0.85M (2 sig figs)
Answer:
0.529
Explanation:
Let's consider the reaction A → Products
Since the units of the rate constant are s⁻1, this is a first-order reaction with respect to A.
We can find the concentration of A at a certain time t (
) using the following expression.
![[A]_{t}=[A]_{0}.e^{-k\times t}](https://tex.z-dn.net/?f=%5BA%5D_%7Bt%7D%3D%5BA%5D_%7B0%7D.e%5E%7B-k%5Ctimes%20t%7D)
where,
[A]₀: initial concentration of A
k: rate constant
![[A]_{t}=0.548M.e^{-3.6\times 10^{-4}s^{-1}\times 99.2s }](https://tex.z-dn.net/?f=%5BA%5D_%7Bt%7D%3D0.548M.e%5E%7B-3.6%5Ctimes%2010%5E%7B-4%7Ds%5E%7B-1%7D%5Ctimes%2099.2s%20%7D)
![[A]_{t}=0.529 M](https://tex.z-dn.net/?f=%5BA%5D_%7Bt%7D%3D0.529%20M)
Answer:
Catalysts
Explanation:
Catalysts lower the aviation energy.
Yes because the sun will make alots of thing grow
Fluorine in compounds is always assigned an oxidation number of -1