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nikdorinn [45]
3 years ago
5

Plz someone help me i dont get this and i need to finish this

Chemistry
1 answer:
Verizon [17]3 years ago
5 0

Answer:

The height of A is 900

Explanation: Beside A, there is a number which explains what the height is so the answer is A.

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Why will a toy train remain still if you push on the engine with
netineya [11]

Explanation:

Because when two equal forces are applied from opposite directions, they "eliminate" each other.

The train would go right if a 3N force was only applied in the right direction, and it would go left if the same force was only applied to the left.

If a 3N force was applied to the right and a 2N force to the left, it would equal a 1N force to the right (3-2=1).

But there it's 3-3=0, so in practice the force is 0N. Therefore the train won't move.

6 0
3 years ago
The boiling point of chloroform is 61.7 C. The enthalapy of vaporization is 31.4 kj/mol. Caculate the entropy of vaporization. D
dedylja [7]

Answer:

Δ S = 93.8 J/mol-K

Explanation:

Given,

Boiling point of chloroform = 61.7 °C

                                             = 273 + 61.7 = 334.7 K.

Enthalapy of vapourization = 31.4 kJ/mol.

Using Gibbs free   energy equation

Δ G = Δ H - T (ΔS)

at equilibrium (when the liquid is boiling), Δ G = 0

so,  0 = ΔH - T (Δ S)

      T (Δ S) = Δ H

and ΔS = ΔH / T

Δ S = (31400 J/mol.) / 334.7 K

Δ S = 93.8 J/mol-K

6 0
3 years ago
HELP please! Which of these describes how heat is transferred by conduction
VLD [36.1K]
D. Air molecules touch the warm ground, heating them up
3 0
3 years ago
A bond where electrons are transferred from a cation to an anion is called a (n) ___________bond.\
emmasim [6.3K]
When elements transfer electrons from a cation and an anion it called ionic bond.
6 0
3 years ago
Determine the molar mass of a compound that has a density of 0.1633 g/L at STP.<br> (show work)
hodyreva [135]

Answer:

                     M.Mass  =  3.66 g/mol

Data Given:

                  M.Mass  =  M = ??

                  Density  =  d  =  0.1633 g/L

                  Temperature  =  T  =  273.15 K (Standard)

                  Pressure  =  P  =  1 atm (standard)

Solution:

              Let us suppose that the gas is an ideal gas. Therefore, we will apply Ideal Gas equation i.e.

                                             P V = n R T    ---- (1)

Also, we know that;

                       Moles  =  n  =  mass / M.Mass

Or,                                   n  =  m / M

Substituting n in Eq. 1.

                                             P V = m/M R T   --- (2)

Rearranging Eq.2 i.e.

                                             P M = m/V R T   --- (3)

As,

                     Mass / Volume = m/V = Density = d

So, Eq. 3 can be written as,

                                             P M = d R T

Solving for M.Mass i.e.

                                             M = d R T / P

Putting values,

M  =  0.1633 g/L × 0.08205 L.atm.K⁻¹.mol⁻¹ × 273.15 K / 1 atm

M  =  3.66 g/mol

6 0
2 years ago
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