Question

A chemist determines by measurements that 0.0900 moles of bromine liquid participate in a chemical reaction. Calculate the mass of bromine liquid that participates Be sure your answer has the correct number of significant digits.

Answer 1

Explanation:

It is known that number of moles equal mass divided by molar mass.

Mathematically,      No. of moles = $\frac{mass}{\text{molar mass}}$

It is given that number of moles is 0.09 mol and molar mass of bromine is 79.904 g/mol.

Therefore, calculate the mass of bromine as follows.

           No. of moles = $\frac{mass}{\text{molar mass}}$

                 0.09 mol = $\frac{mass}{79.904 g/mol}$

                     mass = 7.191 g

Thus, we can conclude that the mass of bromine liquid that participates is 7.191 g.