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attashe74 [19]
3 years ago
8

How do I solve (2x^3)^4?

Mathematics
2 answers:
larisa86 [58]3 years ago
8 0
Hello There!

You would have to do work out 2 to the fourth power.
Also, 3 x 4.
The rules of powers are:
If you have to multiply, you add them
If you have to divide, you subtract them
If they are in brackets like this ^^, you multiply them.

Therefore, your answer is 16^{12}

Hope This Helps You!
Good Luck :) 

- Hannah ❤
Anna11 [10]3 years ago
8 0
The answer to your problem is using Multiplication Distributive Property the formula is (x,Y)^a=x^a y^a and you answer is 16x^12 hope this helps
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How to solve <br> 6x - 17
AveGali [126]

Answer:

you can

Step-by-step explanation:

they are not like terms because the number 6 has and x next to it and 17 doesn't

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3 years ago
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Write an equation that represents degrees fahrenheit in terms of degrees celsius. let xx represent the temperature in degrees ce
IgorC [24]
As we know Conversion from fahrenheit to celsius is
F - 32 =  \frac{9C}{5}

We can write it also as

F =  \frac{9C}{5}+32

F as y and C as x then we can write it as

y =  \frac{9x}{5} + 32
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3 years ago
Use distributive property to rewrite <br><br> 1. 4(x + 9) <br><br> 2. 3 (-2x + 4)
Kobotan [32]

1. 4x+36

2. -6x+12

and aww your pfp

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3 years ago
I need help with #61 to #64 ASAP please and thank you …. Could someone please help me with it… I need to get it done ASAP
aivan3 [116]

Problem 61

The nth triangular number is

T(n) = n(n+1)/2

I'll rewrite this into

T(n) = 0.5n(n+1)

The triangular number right after this is

T(n+1) = 0.5(n+1)(n+2)

I replaced every n with n+1 and simplified

Let's see what we get when we add up the two expressions

T(n) + T(n+1)

0.5n(n+1) + 0.5(n+1)(n+2)

0.5n^2+0.5n + 0.5(n^2+3n+2)

0.5n^2 + 0.5n + 0.5n^2 + 1.5n + 1

n^2+2n+1

(n+1)^2

This shows that the sum of any two consecutive triangular numbers results in a square number

Here's a few examples

  • 0+1 = 1
  • 1+3 = 4
  • 3+6 = 9
  • 6+10 = 16
  • 10+15 = 25

Note each sum is a perfect square, which visually would plot out a square figure.

For quick reference, the set of the first few triangular numbers is {0, 1, 3, 6, 10, 15, 21, 28, 36, 45, 55,...}

<h3>Answer: Square number</h3>

==========================================================

Problem 64

Let's say we go with n = 5.

This means,

T(n) = 0.5n(n+1)

T(n-1) = 0.5(n-1)(n-1+1)

T(n-1) = 0.5n(n-1)

T(5-1) = 0.5*5(5-1)

T(4) = 10

This says that when n = 5, the 4th triangular number is 10

Triple that result and add on n = 5

3*T(4) + n = 3*10+5 = 35

This result is beyond obvious which category of figurate number it belongs to. It's not a triangular number since it's not in the form n(n+1)/2. It's not a square number either.

Through a bit of trial and error, you should find it's a pentagonal number

Pentagonal numbers are of the form n(3n-1)/2

If you plugged n = 5 into that, it leads to 35

n(3n-1)/2 = 5*(3*5-1)/2 = 5*14/2 = 70/2 = 35

The diagram shown below represents the first few pentagonal numbers. The number of blue dots corresponds to the pentagonal number itself. Note the equal spacing when dealing with dots on each segment (eg: some interior blue dots are midpoints, others are quarter points, etc.)

<h3>Answer: Pentagonal number</h3>

8 0
2 years ago
Help please on this question!!
Alika [10]

Answer:

82

Step-by-step explanation:

50+32 =82 and this has to be longer so this is me making it longer

4 0
3 years ago
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