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attashe74 [19]
3 years ago
8

How do I solve (2x^3)^4?

Mathematics
2 answers:
larisa86 [58]3 years ago
8 0
Hello There!

You would have to do work out 2 to the fourth power.
Also, 3 x 4.
The rules of powers are:
If you have to multiply, you add them
If you have to divide, you subtract them
If they are in brackets like this ^^, you multiply them.

Therefore, your answer is 16^{12}

Hope This Helps You!
Good Luck :) 

- Hannah ❤
Anna11 [10]3 years ago
8 0
The answer to your problem is using Multiplication Distributive Property the formula is (x,Y)^a=x^a y^a and you answer is 16x^12 hope this helps
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antoniya [11.8K]
Let the cost of gasoline in the year 2000 be represented b the equation
y = a + b*x
where
x = months, counted from January
y = cost, dollars

The given data in the table is
Month:        Jan  Feb  Mar  Apr  May  Jun  Jul  Aug  Sep  Oct  Nov  Dec
x, months:       1       2     3       4      5       6     7      8      9     10     11      12
y, dollars:     ---      ---     ---     ---   1.76   2.13   ---     ---    ---      ---    ---     ---

When x = 5, y = 1.76.
Therefore
a + 5b = 1.76               (1)

When x = 6, y = 2.13
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a + 6b = 2.13              (2)

Subtract equation (1) from (2).
a + 6b - (a + 5b) = 2.13 - 1.76
b = 0.37

From (1), obtain
a = 1.76 - 5b
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The required equation is
y = 0.37x - 0.09
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Answer: D.  y = 0.37x - 0.09

7 0
3 years ago
A company has a cost equation of c=0.925x^2-4x+20 and a profit equation of p=-1.125x^2+6x+40. Solve for the breakeven point.
lana66690 [7]
0.925x^2 - 4x + 20 = -1.125x^2 + 6x + 40 (at break even point)

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x =  [ - (-10) +/- sqrt(100 - 4*2.05*-20) / (2*2.05) 

x =  6.40, -1.52   Ignore the negative 

Answer is  6.40


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