Answer:
a = 4
b = 3
Explanation:
<u>SOLUTION :-</u>
Balance it by using 'hit & trial' method , and you'll get the answer :-
2Fe₂O + 3C → <u>4</u>Fe + <u>3</u>CO₂
⇒ a = 4 ; b = 3
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<u>VERIFICATION :-</u>
<em>In reactant side of equation :-</em>
- Number of atoms in Fe = 2×2 = 4
- Number of atoms in O = 2×3 = 6
- Number of atoms in C = 3×1 = 3
<em>In product side of equation :-</em>
- Number of atoms in Fe = 4×1 = 4
- Number of atoms in C = 3×1 = 3
- Number of atoms in O = 3×2 = 6
Number of atoms of each element is equal in both reactant & product side of equation. Hence , the equation is balanced.
Mixing water and sugar is a physical change. A physical change is just a change in the form of the substance, whereas a chemical change is when the substance itself changes… chemically. An easy way to figure out which is which is trying to "undo" the change. If it can be undone, it is physical.
Mole fraction is the ratio of the constituent moles to the total constituents. The mole fraction of sodium chloride is 0.0443.
<h3>What is a mole fraction?</h3>
A mole fraction is the proportion of the moles of the component in a total component present.
In 100 gm of solution 13.0 5 means, there is 13.0 gm of sodium chloride present. The mass of water is calculated as,
100 - 13.0 = 87.0 gm
Moles of sodium chloride is calculated as:

Moles of water are calculated as:

Now, moles fraction is calculated by dividing moles of sodium chloride by total moles as,

Therefore, the mole fraction of sodium chloride is 0.0443.
Learn more about mole fraction here:
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The formula can be empirical because the subscripts are reduced to the lowest fraction.
To check if this formula is also the molecular formula we can check by obtaining the molar mass of the compound it is equal to the given molar mass. Thus
12*2 + 4*1 + 16 = 44 g/mol
this is ~equal to the given molar mass thus the given equation can be both empirical and molecular.
Answer: It will take 3 days for half of a 10 g sample to decay.
Explanation:
Half-life of sample of an isotope X = 3 days
Sample decayed = 
N=
, time = t
![\ln[\frac{5}{10}]=-0.231\times t](https://tex.z-dn.net/?f=%5Cln%5B%5Cfrac%7B5%7D%7B10%7D%5D%3D-0.231%5Ctimes%20t)

t = 3 days
It will take 3 days for half of a 10 g sample to decay.