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ser-zykov [4K]
3 years ago
13

Differentiate the types of intermolecular forces

Chemistry
1 answer:
marshall27 [118]3 years ago
6 0

Answer:

  1. Dipole interactions
  2. London dispersion forces
  3. Hydrogen bonds

Credit goes to: chem.libretexts.org

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I have a balloon that can hold 100 liters of air. If I blow up this balloon with 3 miles of gas at a pressure of 1 atmosphere, w
Effectus [21]

Answer:

99

Explanation:

Because if u ask me it has to be

6 0
4 years ago
How many grams of methane gas (CH4) need to be combusted to produce 12.5 L water vapor at 301 K and 1.1 atm? Show all of the wor
tangare [24]
Answer is: 4.45 grams of methane gas <span>need to be combusted</span>.
Balanced chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O.
Ideal gas law: p·V = n·R·T.<span>
p = 1.1 atm.
T = 301 K.
V(H</span>₂O) <span>= 12.5 L.
R = 0,08206 L·atm/mol·K.
</span>n(H₂O) = <span>1.1 atm · 12.5 L ÷ 0,08206 L·atm/mol·K · 301 K.
</span>n(H₂O) = 0.556 mol.
From chemical reaction: n(H₂O) : n(CH₄) = 2 : 1.
n(CH₄) = 0.556 mol ÷ 2 = 0.278 mol.
m(CH₄) = 0.278 mol · 16 g/mol.
m(CH₄) = 4.448 g.
4 0
3 years ago
Please help me. Thank you so much to whoever decides to help me and I love you
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3 0
3 years ago
When 2 grams of powdered lead (IV) oxide was added to 100 cm3 of hydrogen peroxide, water and oxygen were produced. Lead (IV) ox
kirza4 [7]

Answer:

The right answer is:

Replacing the powdered lead oxide with its large crystals

Removing lead (IV) oxide from the reaction mixture

Using 1.0 gram of lead (IV) oxide

Explanation:

Based on the given information this reaction is the catalytic decomposition of H₂O₂ into water and oxygen  using Lead (IV) oxide as a catalyst.

  1. The catalyst surface area is directly proportional to the reaction rate
  • So, Replacing the powdered lead oxide with its large crystals would decrease the reaction rate due to the has larger surface area than its large crystals.

     2. Also, Removing lead (IV) oxide from the reaction mixture  the reaction rate decreased because as the catalyst is removed.

     3.  Using 50 cm³ of hydrogen peroxide  doesn't affect the rate because the concentration of the reactant doesn't change.

     4. Using 1.0 gram of lead (IV) oxide would decrease the reaction rate because the amount of catalyst decreased

So, The right answer is:

Replacing the powdered lead oxide with its large crystals

Removing lead (IV) oxide from the reaction mixture

Using 1.0 gram of lead (IV) oxide

7 0
4 years ago
A large piece of jewelry has a mass of 132.6 g. A graduated cylinder initially contains 48.6 mL water. When the jewelry is subme
Eduardwww [97]

Answer: a) The density of the jewelry will be  0.573g/cm^3

b) The element is silver.

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{Volume}

Given : Mass of jewelry = 132.6  grams

Volume of jewelry = volume of water displaced = (61.2-48.6)=12.6ml

Putting in the values we get:

Density=\frac{132.6g}{12.6ml}=10.52g/ml

Thus density of the jewelry will be 10.52g/ml

As density is characteristic of a particular material , the material must be silver which has a density of 10.5 g/ml.

3 0
4 years ago
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