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Sphinxa [80]
3 years ago
8

Thickening agent used in many foods

Chemistry
1 answer:
Margaret [11]3 years ago
3 0
Cornstarch is most commonly used
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Zinc + Hydrochloric Acid → Zinc Chloride and Hydrogen Gas
Kipish [7]

Explanation:

because in the right side there is 2 hydrogen( H) and 2 chloride (Cl) to balace them we have to replace 2.

3 0
3 years ago
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Calculate the mass of 2.50 mol of methanol.
solmaris [256]

Answer:

60g

Explanation:

Moles = mass / mollar mass

Mass = Moles x mollar mass

Mass = 2.50 x 24

Mass = 60g

7 0
3 years ago
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Enzymes in the small intestine break down proteins, carbohydrates, and lipids. These enzymes are named after the substrate they
svetoff [14.1K]

The enzymes and their respective substrates are as follows:

  • Protease enzymes such as trypsin and chymotrypsin break down proteins
  • Carbohydrate enzymes such amylase and maltase break down carbohydrates
  • Lipase enzyme breaks down lipids.

In the small intestine, a protease enzyme known as chymotrypsin breaks down protein, pancreatic amylase breaks down carbohydrates, while pancreatic lipase breaks down lipids.

More on biological enzymes can be found here: brainly.com/question/12194042

7 0
2 years ago
Combustion vapor-air mixtures are flammable over a limited range of concentrations. The minimum volume % of vapor that gives a c
DochEvi [55]
Combustion equation of n-hexane:

2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O

a)
Assuming we have 100 moles of air,
Oxygen = 20.9 moles
n-hexane required = 20.9/19 x 2
= 2.2 moles

LFL = Half of stoichometric amount = 2.2 / 2 = 1.1
LFL n-hexane = 1.1% 

b)
1.1 volume percent required for LFL

1.1% x 1
= 0.0011 m³ of n-hexane required
6 0
3 years ago
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After decaying for 48 hours, one-sixteenth (1/16) of the original mass of a radioisotope sample remains unchanged. What is the h
Hunter-Best [27]

The half-life of this radioisotope : 12 hr

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually radioactive elements have an unstable atomic nucleus.  

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

t = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

t=48 hr

\tt \dfrac{Nt}{No}=\dfrac{1}{16}

The half-life :

\tt \dfrac{1}{16}=\dfrac{1}{2}^{(48/t\frac{1}{2} )}\\\\(\dfrac{1}{2})^4=(\dfrac{1}{2})^{48/t\frac{1}{2}}\\\\4=48/t\frac{1}{2}\\\\t\frac{1}{2}=12~hr

7 0
2 years ago
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