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oksano4ka [1.4K]
3 years ago
11

calculate the amount of H2O2:Using the balanced equation, calculate the number of moles of H2O2present in the initial solution.

Calculate the molar mass of H2O2and determine the grams of H2O2present in the initial solution.
Chemistry
1 answer:
arlik [135]3 years ago
4 0

Answer: molar mass of H2O2 = 34 g/mol

mass of H2O2 = 68 grams

Explanation:

The decomposition reaction of Hydrogen peroxide (H2O2) is:

                                     2 H2O2   →    2 H2O   +   O

According to the equation the numbers of moles of  H2O2 is 2 moles.

The molar mass of H2O2 = ( 16×2) + (1x2)

                                                32 + 2 = 34 g/mol

∵ atomic mass of oxygen is 16 and hydrogen is 1.

Now, mole=\frac{mass-in-gram }{molar mass}

putting values

           2=\frac{mass}{34}

mass of H2O2 = 2 × 34 = 68 grams

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3 years ago
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Answer:

1 = Q =  7315 j

2 =Q =  -21937.5 j

Explanation:

Given data:

Mass of water = 50 g

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Energy required to change the temperature = ?

Solution:

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It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of water is 4.18 j/g.°C.

Formula:

Q = m.c. ΔT

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ΔT = T2 - T1

ΔT = 55°C - 20°C

ΔT = 35°C

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Q 2:

Given data:

Mass of metal = 100 g

Initial temperature = 1000°C

Final temperature = 25°C

Energy released = ?

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ΔT = -975°C

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Q = 100 g × 0.225 j/g.°C × -975°C

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Negative sign show that energy is released.

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