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2 years ago

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Chemistry

1 answer:

jok3333 [9.3K]2 years ago

5 0

Answer:

Early-warning systems are essential in the case of hurricanes, severe thunderstorms, tornadoes, tsunamis, and volcanoes. All of these can wreak havoc! Let’s take a look at how meteorologists forecast these events and how early-warning systems can help us protect ourselves if we are in their paths.

Explanation:

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Citric acid (C6H8O7) is a triprotic acid (It has 3 protons that can dissociate when dissolved) found naturally in lemon juice, a

Gnesinka [82]

<u>Answer:</u> The molarity of citric acid that is commercially available lemon juice is 0.416 M

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $C_6H_8O_7$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=3\\M_1=?M\\V_1=20.00mL\\n_2=1\\M_2=1.751M\\V_2=14.26mL$

Putting values in above equation, we get:

$3\times M_1\times 20.00=1\times 1.751\times 14.26\\\\M_1=\frac{1\times 1.751\times 14.26}{3\times 20.00}=0.416M$

Hence, the molarity of citric acid that is commercially available lemon juice is 0.416 M

4 0

2 years ago

What atomic component contributes to many of the trends of elements

aivan3 [116]

what??? i need more information

3 0

2 years ago

Calculate the mass of ethyl alcohol required to prepare 540 grams of C4H6, if the reaction follows the scheme:

kkurt [141]

Answer:

Explanation:

2C₂H₅OH = C₄H₆ + 2H₂O + H₂

2 mole 1 mole

molecular weight of ethyl alcohol

mol weight of C₂H₅OH = 46 gm

mol weight of C₄H₆ 54 gm

540 gm of C₄H₆ = 10 mole

10 mole of C₄H₆ will require 20 mol of ethyl alcohol .

20 mole of ethyl alcohol = 20 x 46

= 920 gm

ethyl alcohol required = 920 gm .

3 0

2 years ago

How many grams of ammonia (NH3) can be produced by the synthesis of excess hydrogen gas (H2) and 253.8 grams of nitrogen gas (N2

kogti [31]

Answer:

308.2 g of NH₃.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

3H₂ + N₂ —> 2NH₃

Next, we shall determine the mass of N₂ that reacted and the mass of NH₃ produced from the balanced equation. This can be obtained as follow:

Molar mass of N₂ = 2 × 14 = 28 g/mol

Mass of N₂ from the balanced equation = 1 × 28 = 28 g

Molar mass of NH₃ = 14 + (3×1)

= 14 + 3 = 17 g/mol

Mass of NH₃ from the balanced equation = 2 × 17 = 34 g

Summary:

From the balanced equation above,

28 g of N₂ reacted to produce 34 g of NH₃.

Finally, we shall determine the mass of NH₃ produced by the reaction of 253.8 g of N₂. This can be obtained as illustrated below:

From the balanced equation above,

28 g of N₂ reacted to produce 34 g of NH₃.

Therefore, 253.8 g of N₂ will react to produce = (253.8 × 34)/28 = 308.2 g of NH₃.

Thus, 308.2 g of NH₃ were obtained from the reaction.

8 0

2 years ago

Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch

Salsk061 [2.6K]

Answer:

kp= 3.1 x 10^(-2)

Explanation:

To solve this problem we have to write down the reaction and use the ICE table for pressures:

2SO2 + O2 ⇄ 2SO3

Initial 3.4 atm 1.3 atm 0 atm

Change -2x - x + 2x

Equilibrium 3.4 - 2x 1.3 -x 0.52 atm

In order to know the x value:

2x = 0.52

x=(0.52)/2= 0.26

2SO2 + O2 ⇄ 2SO3

Equilibrium 3.4 - 0.52 1.3 - 0.26 0.52 atm

Equilibrium 2.88 atm 1.04 atm 0.52 atm

with the partial pressure in the equilibrium, we can obtain Kp.

$Kp=\frac{PSO3^2}{PSO2^2 PO2}=\frac{(0.52)^2}{(2.88)^2(1.04)}=0.03135$

8 0

2 years ago