Phosgene on reacting with <span>phenylmagnesium bromide generates
benzoyl chloride.
Since, </span>phenylmagnesium bromide is added in excess. It would further react with benzoyl chloride to form
benzophenone.
Benzophenone on further reacting with phenylmagnesium bromide, and aqueous treatment, gives
triphenylmethanol.
Entire reaction pathways is shown below:
Answer:
<h3>The answer is option D</h3>
Explanation:
To find the speed given the kinetic energy and mass we use the formula
where
m is the mass
v is the speed
From the question
KE = 15 J
m = 2.3 kg
We have
We have the final answer as
<h3>3.6 m/s</h3>
Hope this helps you
The answer is As2O5
good luck
Answer:
The answers are in the explanation
Explanation:
A buffer is the mixture of a weak acid with its conjugate base or vice versa. Thus:
<em>1)</em> Mixing 100.0 mL of 0.1 M HF with 100.0 mL of 0.05 M mol KF. <em>Will </em>result in a buffer because HF is a weak acid and KF is its conjugate base.
<em>2)</em> Mixing 100.0 mL of 0.1 M NH₃ with 100.0 mL of 0.1 M NH₄Br. <em>Will not </em>result in a buffer because NH₃ is a strong base.
<em>3) </em>Mixing 100.0 mL of 0.1 M HCN with 100.0 mL of 0.05 M KOH. <em>Will </em>result in a buffer because HCN is a weak acid and its reaction with KOH will produce CN⁻ that is its conjugate base.
<em>4)</em> Mixing 100.0 mL of 0.1 M HCl with 100.0 mL of 0.1 M KCl <em>Will not </em>result in a buffer because HCl is a strong acid.
<em>5)</em> Mixing 100.0 mL of 0.1 M HCN with 100.0 mL of 0.1 M KOH <em>Will not </em>result in a buffer because each HCN will react with KOH producing CN⁻, that means that you will have just CN⁻ (Conjugate base) without HCN (Weak acid).
I hope it helps!
