Answer:
The given grammar is :
S = T V ;
V = C X
X = , V | ε
T = float | double
C = z | w
1.
Nullable variables are the variables which generate ε ( epsilon ) after one or more steps.
From the given grammar,
Nullable variable is X as it generates ε ( epsilon ) in the production rule : X -> ε.
No other variables generate variable X or ε.
So, only variable X is nullable.
2.
First of nullable variable X is First (X ) = , and ε (epsilon).
L.H.S.
The first of other varibles are :
First (S) = {float, double }
First (T) = {float, double }
First (V) = {z, w}
First (C) = {z, w}
R.H.S.
First (T V ; ) = {float, double }
First ( C X ) = {z, w}
First (, V) = ,
First ( ε ) = ε
First (float) = float
First (double) = double
First (z) = z
First (w) = w
3.
Follow of nullable variable X is Follow (V).
Follow (S) = $
Follow (T) = {z, w}
Follow (V) = ;
Follow (X) = Follow (V) = ;
Follow (C) = , and ;
Explanation:
Answer:
You can create high drag which allows a steeper angle without increasing your air speed on landing. you can reduce the length of landing role. Flaps are also used to increase the drag they are retracted when they are not needed. it is adviseable to down he flaps during the time of take off.
Answer:
Diode equation for reverse saturation current
Voltage at which diode goes into Resistive region:V=-5 volts
Voltage at which high level injection occurs:Va=0.55 volt
Voltage at which avalanche multiplication occurs:V=5volts
Explanation:
we take here forward and reverse 0.7 volt and -5 volt
As Diode current equation is express as
....................1
here
is total current through the diode and
is reverse saturated current and
is voltage drop across diode and
is idealized factor and
is thermal voltage
so here we know that when Bios is forward than
=
.................2
ans Bios is Reverse than
=
..................3
so here
1. diode reverse saturation current is express as
and
2. Voltage at which diode go into Reverse behavior will be
=
= -5 volt
and
3. voltage at which high level injection occur that is
Va = 0.55 volt
and
4. voltage at which avalanche multiplication occurs is
Va = 5 volt