The forming section of a plastics plant puts out a continuous sheet of plastic that is 1.2 m wide and 2 mm thick at a rate of 15
m/min. The temperature of the plastic sheet is 908C when it is exposed to the surrounding air, and the sheet is subjected to air flow at 308C at a velocity of 3 m/s on both sides along its surfaces normal to the direction of motion of the sheet. The width of the air cooling section is such that a fixed point on the plastic sheet passes through that section in 2 s. Determine the rate of heat transfer from the plastic sheet to the air.
1 answer:
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Answer: Equilibrium temperature they reach is 383 K
Explanation:
As we know that,
.................(1)
where,
q = heat absorbed or released
= mass of gold = 1.3 kg
= mass of copper = 2.1 kg
= final temperature = ?
= temperature of gold= 300 K
= temperature of copper = 400 K
= specific heat of gold =
= specific heat of copper =
Now put all the given values in equation (1), we get
Thus equilibrium temperature they reach is 383 K