The forming section of a plastics plant puts out a continuous sheet of plastic that is 1.2 m wide and 2 mm thick at a rate of 15
m/min. The temperature of the plastic sheet is 908C when it is exposed to the surrounding air, and the sheet is subjected to air flow at 308C at a velocity of 3 m/s on both sides along its surfaces normal to the direction of motion of the sheet. The width of the air cooling section is such that a fixed point on the plastic sheet passes through that section in 2 s. Determine the rate of heat transfer from the plastic sheet to the air.
1 answer:
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Answer:
Qcd=0.01507rad
QT= 0.10509rad
Explanation:
The full details of the procedure and answer is attached.
Answer:
investment 10 years from now is $1,238,000 .
Explanation:
given data
sum = $500,000
rate = 12% =0.12
total time = 10 year
solution
as present value After 2 years from now is $500,000
so time period is now = 8 year ( 10 - 2 )
so we apply future value formula that is
Future value = present value × ............1
put here value we get
Future value = $500,000 ×
Future value = $500,000 × 2.476
Future value = $1,238,000
so investment 10 years from now is $1,238,000 .