Answer:
A
Explanation:
A because you are continuing to keep moving and thinking.
Answer:
The force induced on the aircraft is 2.60 N
Solution:
As per the question:
Power transmitted, ![P_{t} = 8 kW = 8000 W](https://tex.z-dn.net/?f=P_%7Bt%7D%20%3D%208%20kW%20%3D%208000%20W)
Now, the force, F is given by:
(1)
where
v = velocity
Now,
For a geo-stationary satellite, the centripetal force,
is provided by the gravitational force,
:
![F_{c} = F_{G}](https://tex.z-dn.net/?f=F_%7Bc%7D%20%3D%20F_%7BG%7D)
![\frac{mv^{2}}{R} = \frac{GM_{e}m{R^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7Bmv%5E%7B2%7D%7D%7BR%7D%20%3D%20%5Cfrac%7BGM_%7Be%7Dm%7BR%5E%7B2%7D%7D)
Thus from the above, velocity comes out to be:
![v = \sqrt{\frac{GM_{e}}{R}}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B%5Cfrac%7BGM_%7Be%7D%7D%7BR%7D%7D)
![v = \sqrt{\frac{6.67\times 10^{- 11}\times 5.979\times 10^{24}}{42166\times 10^{3}}} = 3075.36 m/ s](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B%5Cfrac%7B6.67%5Ctimes%2010%5E%7B-%2011%7D%5Ctimes%205.979%5Ctimes%2010%5E%7B24%7D%7D%7B42166%5Ctimes%2010%5E%7B3%7D%7D%7D%20%3D%203075.36%20m%2F%20s)
where
R = ![R_{e} + H](https://tex.z-dn.net/?f=R_%7Be%7D%20%2B%20H)
R = ![\sqrt{GM_{e}(\frac{T}{2\pi})^{2}}](https://tex.z-dn.net/?f=%5Csqrt%7BGM_%7Be%7D%28%5Cfrac%7BT%7D%7B2%5Cpi%7D%29%5E%7B2%7D%7D)
where
G = Gravitational constant
T = Time period of rotation of Earth
R is calculated as 42166 km
Now, from eqn (1):
![8000 = F\times 3075.36](https://tex.z-dn.net/?f=8000%20%3D%20F%5Ctimes%203075.36)
F = 2.60 N
Answer: 1766.667 Ω = 1.767kΩ
Explanation:
V=iR
where V is voltage in Volts (V), i is current in Amps (A), and R is resistance in Ohms(Ω).
3mA = 0.003 A
Rearranging the equation, we get
R=V/i
Now we are solving for resistance. Plug in 0.003 A and 5.3 V.
R = 5.3 / 0.003
= 1766.6667 Ω
= 1.7666667 kΩ
The 6s are repeating so round off to whichever value you need for exactness.
Answer:
you fill the hole so there is no more cat