Answer:
1/5 + 2/5 i sqrt(6) = .2 + .98i
1/5 - 2/5 i sqrt(6) = .2 - .98i
Step-by-step explanation:
5z^2−9z=−7z−5
We need to get all the terms on one side (set the right side equal to zero)
Add 7z to each side
5z^2−9z+7z=−7z+7z−5
5z^2−2z=−5
Add 5 to each side
5z^2−2z+5=−5 +5
5z^2−2z+5=0
This is in the form
az^2 +bz+c = 0 so we can use the quadratic formula
where a = 5 b = -2 and c = 5
-b± sqrt(b^2-4ac)
-------------------------
2a
-(-2)± sqrt((-2)^2-4(5)5)
-------------------------
2(5)
2± sqrt(4-100)
-------------------------
10
2± sqrt(-96)
-------------------------
10
2± sqrt(16)sqrt(-1) sqrt(6)
-------------------------
10
2± 4i sqrt(6)
-------------------------
10
1/5 ± 2/5 i sqrt(6)
Splitting the ±
1/5 + 2/5 i sqrt(6) = .2 + .98i
1/5 - 2/5 i sqrt(6) = .2 - .98i
Answer:
x=-2
Step-by-step explanation:
6(x + 1) = -2(3x + 9)
Distribute 6 and -2.
6x+6=-6x-18
Move the variable to the left-hand side and move the constant to the right and change their signs.
6x+6x=-18-6
Collect like terms.
12x=-24
Divide both sides of the equation by 12.
x=-2
Hope this helps :)
Answer:
6 cm by 17 cm
Step-by-step explanation:
The area is the product of the dimensions; the perimeter is double the sum of the dimensions.
So, we want to find two numbers whose product is 102 and whose sum is 23.
102 = 1·102 = 2·51 = 3·34 = 6·17
The last of these factor pairs has a sum of 23.
The dimensions are 6 cm by 17 cm.
Answer:
Domain: 337, 674, 1011, 1348
Range: 1,2,3,4
