All categories

2 years ago

An electric wall clock has a second hand 15 cm long. at the tip of his hand, what is the magnitude of the velocity?

Physics

1 answer:

Mila [183]2 years ago

7 0

The velocity of the tip of the second hand is 0.0158 m/s

Explanation:

First of all, we need to calculate the angular velocity of the second hand.

We know that the second hand completes one full circle in

T = 60 seconds

Therefore, its angular velocity is:

$\omega = \frac{2\pi}{T}=\frac{2\pi}{(60)}=0.105 rad/s$

Now we can calculate the velocity of a point on the tip of the hand by using the formula

$v=\omega r$

where

$\omega=0.105 rad/s$ is the angular velocity

r = 15 cm = 0.15 m is the radius of the circle (the distance of the point from the centre of rotation)

Substituting,

$v=(0.105)(0.15)=0.0158 m/s$

Learn more about angular motion here:

brainly.com/question/9575487

brainly.com/question/9329700

brainly.com/question/2506028

#LearnwithBrainly

You might be interested in

A rigid dam is composed of material of SG = 5 . The dam height is 20 m . What is the minimum thickness b of the dam necessary to

Kay [80]

Answer:

b = 5.164 m is the minimum thickness of the dam

Explanation:

Given

SG = 5

h = 20 m

b = ?

w = 1 m

γw = 9800 N/m³

We can get the forces as follows

Fp = γw*(h/2)*(h*w)

⇒ Fp = (9800 N/m³)*(20 m/2)*(20 m*1 m) = 1.96*10⁶N

W = (SG*γw)*(h*b*w)

⇒ W = (5*9800 N/m³)*(20 m*b*1 m) = (9.8*10⁵N/m)*b

Then, we apply

∑M₀ = 0 (counterclockwise)

- Fp*(h/3) + W*(b/2) = 0

⇒ - 1.96*10⁶N*(20 m/3) + (9.8*10⁵N/m)*b*(b/2) = 0

- 13.066*10⁶N-m + (4.9*10⁵N/m)*b² = 0

⇒ b = 5.164 m is the minimum thickness of the dam

3 0

3 years ago

A specific amount of energy is emitted when excited electrons in an atom in a sample of an element return to the ground state. T

Flauer [41]

Answer:

C. identity of the element

The specific amount of energy emitted when electrons jump from excited states to the ground state refers to emission spectrum. The energy is emitted in the form of photons, and the photons have very specific wavelengths (energy) that correspond to the energy gaps between the excited states and the ground state. The specific wavelengths of light emitted are referred to as the "emission spectrum," and each element produces a different emission spectrum. Thus, this emitted energy can be used to identify the element from which your sample was taken.

Explanation:

6 0

1 year ago

True or False: Litmus paper turns blue in bases and red in acids. <br>True <br>False

lutik1710 [3]

False because bases turn red litmus paper to blue and acids turn blue litmus paper red

8 0

1 year ago

Jet aircraft maintenance crews are required to wear protective earplugs. Members of a particular crew wear earplugs that reduce

Taya2010 [7]

Answer:

So the sound intensity level they would experience without the earplugs is 110.32dB.

Explanation:

Given data

Sound intensity by factor =215

Sound intensity level =87 dB

To find

Sound intensity level they would experience without the earplugs

Solution

First we need to find the new sound intensity level

$I_{n}=215(10^{\frac{87}{10} } )\\I_{n}=1.08*10^{11})$

The dB can be calculated as:

$dB=10log(I_{n})\\$

Substitute the given values

$dB=10log(1.08*10^{11})\\dB=110.32dB$

So the sound intensity level they would experience without the earplugs is 110.32dB.

7 0

3 years ago

An atom emission of light with a specific amount of energy confirms that ?

marusya05 [52]

The correct answer is B, electrons emit and absorb energy based on their position around the nucleus.

8 0

3 years ago