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4 years ago

Two stars orbit each other in a _ solar system

Physics

2 answers:

emmasim [6.3K]4 years ago

5 0

I think moon I'm not sure. But I think it's moon

Brilliant_brown [7]4 years ago

4 0

This is a binary star system

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A wheel starts from rest and rotates with constant angular acceleration to reach an angular speed of 12.9 rad/s in 2.98 s.

PtichkaEL [24]

Explanation:

(a) Find the magnitude of the angular acceleration of the wheel.

angular acceleration = angular speed /time
angular acceleration = 12.9/2.98 = 4.329rad/s²

(b) Find the angle in radians through which it rotates in this time interval.

angular speed = 2x3.14xf
12.9rad = 2 x3.14

rad = 6.28/12.9
rad = 0.487

Now we convert rad to angle

1 rad = 57.296°
0.487 = unknown angle
unknown angle =57.296 x 0.487 = 27.9°

The angle in radians = 27.9°

8 0

3 years ago

The angular velocity of a process control motor is (13−12t2) rad/s, where t is in seconds. Part A At what time does the motor re

mihalych1998 [28]

Answer:

Explanation:

Given

$\omega =13-\frac{1}{2}\cdot t^2$

Motor reverse its direction when \omega =0

$13-0.5t^2=0$

$26=t^2$

$t=\sqrt{26}=5.099\approx 5.1 s$

(b)

$\frac{\mathrm{d} \theta }{\mathrm{d} t}=\omega$

$\int d\theta =\int_{0}^{5.1}\omega dt$

$\int d\theta =\int_{0}^{t}(13-.05t^2)dt$

$\theta =(13t-0.1667\times t^3)_0^{5.1}$

$\theta =44.192^{\circ}$

4 0

3 years ago

The movement of particles from high to low concentration. True or False

Digiron [165]

Question:

Diffusion is the movement of particles from high to low concentration. True or False

Answer:

True.

Explanation:

Diffusion is a process that allows the movement of substance or particles in and out of cells through a semipermeable membrane.

Diffusion is a process that allows the spread or movement of particles from the region of higher concentration to a region of lower concentration through a semipermeable membrane.

Diffusion only occurs in gases and solution but not in solids, it also occurs only where particles can move freely.

Note: When particles move from the region of higher concentration to a lower concentration, it gives room for even, uniform and random distribution of particles.

8 0

3 years ago

A 4.2-m-diameter merry-go-round is rotating freely with an angular velocity of 0.79 rad/s . Its total moment of inertia is 1790

Nezavi [6.7K]

Answer:

$w_2=0.467rad/s$

Explanation:

Four people standing on the ground each of mass and usually this questions have to find the final angular velocity

$m_t=4*70kg=280kg$

The radius $r=4.2/2=2.1m$

Angular velocity $w_1=0.79rad/s$

The moment of inertia total is $I_t=1790 kg/m^2$

Momento if inertia

$I_1=m_t*r^2$

$I_1=280kg*(2.1m)^2=1234.8kg*m^2$

Angular momentum

$I_1*w_1=I_t*w_2$

Solve to w2

$w_2=\frac{I_1*w_1}{I_t}$

$w_2=\frac{1790kg*m^2*0.79rad/s}{3024.8kg*m^2}$

$w_2=0.467rad/s$

8 0

3 years ago

Using the strap at an angle of 31.0° above the horizontal, a Grade 12 Physics student, tired from studying, is dragging his 15.0

lora16 [44]

Answer:

Explanation:

The question is incomplete. Here is the complete question.

Using the strap at an angle of 31° above the horizontal, a Grade 12 Physics student, tired from studying, is dragging his 15 kg school bag across the floor at a constant velocity. (a) If the force of tension in the strap is 51 N, what is the normal force.

Check the diagram related to the question in the attachment below for better understanding.

The normal force is the reaction acting perpendicular to the force of tension in the strap and opposite the weight of the bag. They are the forces acting along the vertical.

The normal force N will be the sum of the force of tension acting along the vertical (Ty) and the weight of the bag (W).

Ty = 15sin31°

Ty = 7.73N

W = mass * acceleration due to gravity

W = 15.0*9.8

W = 147N

The normal force is therefore expressed as;

N = Ty + W

N = 7.73 + 147

N = 154.73N

3 0

3 years ago