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Sliva [168]
3 years ago
13

Convert 285,000 milliliters to decaliters.​

Physics
2 answers:
ElenaW [278]3 years ago
6 0

Answer:

The answer is 28.5 decaliters

Rudiy273 years ago
5 0
The answer is 28.5 decaliters. Hope this helps
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The difference between an experimental value and an accepted value is
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Answer:

HERE'S MY UNDERSTANDING OF THE DIFFERENCE

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Identify the theory that can be used to explain each phenomenon.
ahrayia [7]

Answer:

Diffraction: Wave Theory

Interference: Wave Theory

Reflection: both particles and wave theories

Refraction: both particles and wave theories

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3 years ago
The speed of an object is given by v = 5.00t^2 + 4.00t where v is in m/s and t is in s. What is the acceleration of the object a
nexus9112 [7]
The speed is 
v = 5t² + 4t
where 
v is in m/s, and t in s.

The acceleration is the derivative of the velocity. It is
a = 10t + 4

When t = 2 s, the acceleration is
a(2) = 10*2 +4 = 24 m/s²

Answer: 24 m/s²
8 0
3 years ago
Infrared radiation from young stars can pass through the heavy dust clouds surrounding them, allowing astronomers here on Earth
liberstina [14]

Answer:

λ = 1.86 x 10⁻⁴ m = 186 μm

Explanation:

The relationship between the wavelength and the frequency of a wave is given by the following equation:

c = f\lambda\\\\\lambda = \frac{c}{f}

where,

λ = wavelength of infrared radiation = ?

c = speed of infrared radiation = speed of light = 3 x 10⁸ m/s

f = frequency of infrared radiation = 1.61 THz = 1.61 x 10¹² Hz

Therefore,

\lambda = \frac{3\ x\ 10^8\ m/s}{1.61\ x\ 10^{12}\ Hz}

<u>λ = 1.86 x 10⁻⁴ m = 186 μm</u>

7 0
3 years ago
A 22-g bullet traveling 265 m/s penetrates a 1.9 kg block of wood and emerges going 125 m/s .
Usimov [2.4K]

The body moves at a velocity of 1.62m/s after the bullet emerges.

<h3>Given:</h3>

Mass of bullet, m_1 = 22g

                               = 0.022 kg

Mass of the block, m_2 = 1.9 kg

Velocity of bullet , v_1 = 265 m/s

v_2 = 0

According to the law of collision which states that the momentum of the body before the collision is equal to the momentum of the body after the collision.

After penetration;

v^{'}_1 =125 m/s

v^{'}_2=?

The formula for calculating the collision of a body is expressed as:

p = mv

m is the mass of the body

v is the velocity of the body

∴ Momentum before = Momentum after

Substitute the given parameters into the formula as shown:

   m_1v_1+ m_2v_2 = m_1v^{'}_1+ m_2v^{'}_2\\0.022* 265 + 0 = 0.022*125+1.9*v^{'}_2\\5.83 = 1.9 v^{'}_2\\v^{'}_2 = 1.62 m/s

Therefore, It moves with a velocity of 1.62 m/s.

Learn more about momentum here:

brainly.com/question/25121535

#SPJ1

6 0
2 years ago
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