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Mandarinka [93]
3 years ago
10

I have 2 questions:

Chemistry
2 answers:
lara [203]3 years ago
7 0
The reactivity depends on the elements valence electrons. The need to be stable will make an element become more reactive, In order for an atom to be stable, it needs 8 valence electrons in its outer shell. 

Since Calcium is in group 2, it has 2 valence electrons, and would rather give up the electrons. While Sulfur has 6, it would need to gain 2 more to be stable, making it more reactive. 
kirill [66]3 years ago
6 0
An atoms valence is the amount of electrons in the outer ring and atoms like to have a valence of 8 so the closer to having 8 in the outer ring the more reactive the atom is so since both elements are 2 away from a valence of 8 theyre equally reactive
You might be interested in
How many moles of Ammonium Sulfate can be made from 30.0mol of NH3? 2NH3 + H2SO4 --> (NH4)2SO4
BartSMP [9]

Answer: 15.0 moles of (NH_4)_2SO_4 are formed from  30.0 mol of NH_3

Explanation:

The balanced chemical reaction is :

2NH_3+H_2SO_4\rightarrow (NH_4)_2SO_4

According to stoichiometry :

2 moles of NH_3 give = 1 mole of (NH_4)_2SO_4

Thus 30.0 moles of NH_3 will give =\frac{1}{2}\times 30.0=15.0moles  of (NH_4)_2SO_4

Thus 15.0 moles of (NH_4)_2SO_4 are formed from  30.0 mol of NH_3

7 0
3 years ago
Draw a molecular model of sulfur trioxide.
bija089 [108]

Answer:

Here's what I get  

Explanation:

The Lewis structure of SO₃ consists of a central sulfur atom double-bonded to each of three oxygen atoms that points to the corners of an equilateral triangle.

A ball-and-stick model of SO₃ is shown below.

6 0
3 years ago
The molarity (M) of an aqueous solution containing 22.5 g of sucrose (C12H22O11) in 35.5 mL of solution is ________.
Nonamiya [84]

Answer:

1.86 M

Explanation:

From the question given above, the following data were obtained:

Mass of sucrose (C12H22O11) = 22.5 g

Volume of solution = 35.5 mL

Molarity of solution =?

Next, we shall determine the number of mole in 22.5 g of sucrose (C12H22O11). This can be obtained as follow:

Mass of sucrose (C12H22O11) = 22.5 g

Molar mass of C12H22O11 = (12×12) + (22×1) + (16×11)

= 144 + 22 + 176

= 342 g/mol

Mole of C12H22O11 =?

Mole = mass /Molar mass

Mole of C12H22O11 = 22.5 /342

Mole of sucrose (C12H22O11) = 0.066 mole

Next, we shall convert 35.5 mL to litres (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

35.5 mL = 35.5 mL × 1 L / 1000 mL

35.5 mL = 0.0355 L

Thus, 35.5 mL is equivalent to 0.0355 L.

Finally, we shall determine the molarity of the solution as follow:

Mole of sucrose (C12H22O11) = 0.066 mole

Volume of solution = 0.0355 L.

Molarity of solution =?

Molarity = mole /Volume

Molarity of solution = 0.066/0.0355

Molarity of solution = 1.86 M

Therefore, the molarity of the solution is 1.86 M.

8 0
3 years ago
Grams of sodium 9.5g in NaCl <br>​
Kitty [74]

Answer:

3.68 grams.

Explanation:

First we <u>convert 9.5 g of NaCl into moles of NaCl</u>, using its<em> molar mass</em>:

9.5 g ÷ 58.44 g/mol = 0.16 mol NaCl

In<em> 0.16 moles of NaCl there are 0.16 moles of sodium </em>as well.

We now <u>convert 0.16 moles of sodium into grams</u>, using <em>sodium's molar mass</em>:

0.16 mol * 23 g/mol = 3.68 g

4 0
2 years ago
I'll GIVE YOU THE BRAINLIEST!!!!!!!!!!!!!!!!!!!!
ahrayia [7]
Sea arch, headland, sea cave, cliff, sea stack sorry if I’m wrong hope this helped
3 0
2 years ago
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