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Mandarinka [93]
4 years ago
10

I have 2 questions:

Chemistry
2 answers:
lara [203]4 years ago
7 0
The reactivity depends on the elements valence electrons. The need to be stable will make an element become more reactive, In order for an atom to be stable, it needs 8 valence electrons in its outer shell. 

Since Calcium is in group 2, it has 2 valence electrons, and would rather give up the electrons. While Sulfur has 6, it would need to gain 2 more to be stable, making it more reactive. 
kirill [66]4 years ago
6 0
An atoms valence is the amount of electrons in the outer ring and atoms like to have a valence of 8 so the closer to having 8 in the outer ring the more reactive the atom is so since both elements are 2 away from a valence of 8 theyre equally reactive
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Formula equation is more informative than a word equation why​
Taya2010 [7]

Answer:

yes

Explanation:

this is because the formula equation shows the details on how they solved the equation

6 0
3 years ago
1. What is a source of new alleles in natural populations?
scoray [572]

Explanation:

Generally, mating outside of a given population can give different alleles. Mutations and the crossing over of chromatids can add difference to the genetic pool.

8 0
3 years ago
In the front of the room, there is a bottle that contains a 32.00 g sample of sulfur. This is
Vera_Pavlovna [14]
6.02x10^23 atoms is the answer
8 0
3 years ago
B. Calculate how many atoms of hydrogen are in 1. 75 moles of glucose (c6h12o6).
ycow [4]

Answer:

1.26x10^25 atoms of hydrogen

Explanation:

because there are 12 atoms of hydrogen in a molecule of glucose, multiply 12 by Avogadro's number (6.02x10^23) to get how many molecules of hydrogen there are in a mole of glucose. Then multiply that number by 1.75, which is the number of moles of glucose there is in this problem.

4 0
3 years ago
Using the standard enthalpies of formation found in the textbook, determine the enthalpy change for the combustion of ethanol c2
ArbitrLikvidat [17]
Enthalpy of formation is calculated by subtracting the total enthalpy of formation of the reactants from those of the products. This is called the HESS' LAW.
ΔHrxn = ΔH(products) - ΔH(reactants)

Since the enthalpies are not listed in this item, from reliable sources, the obtained enthalpies of formation are written below.
ΔH(C2H5OH) = -276 kJ/mol
ΔH(O2) = 0 (because O2 is a pure substance)
ΔH(CO2) = -393.5 kJ/mol
ΔH(H2O) = -285.5 kJ/mol

Using the equation above,
ΔHrxn = (2)(-393.5 kJ/mol) + (3)(-285.5 kJ/mol) - (-276 kJ/mol)
ΔHrxn = -1367.5 kJ/mol

<em>Answer: -1367.5 kJ/mol</em>
6 0
3 years ago
Read 2 more answers
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