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harkovskaia [24]

2 years ago

5

Anyone who can answer this for me ill give 35 pts

1 answer:

Andru [333]2 years ago

7 0

Answer:

x^3+3x^2+4x+5

Step-by-step explanation:

Ok, so what helps me solve this kind of problem is to circle, underline, or box the like terms(the ones with the same exponent and variable). Be sure to note the sign of each term when combining like terms. take it one step at a time, and work downwards starting with the highest exponent. You have -x^3 and +2x^3, which is x^3. Next, you have +2x^2 and +x^2, which is 3x^2. You should write down each of these as you go, so you should now have x^3+3x^2. Then combine the terms with no exponent but with x, which is 5x and -1x, which is +4x. You should have x^3+3x^2+4x now. Lastly, just combine the numbers 1, -1, and 5, which is 5. This gives you an answer of x^3+3x^2+4x+5.

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In a social club, the ratio of men to women is 5: 7. There are 595 women. How

gregori [183]

Answer:

52

you take 5 ÷ it by 7 the ×it by 595

8 0

2 years ago

A city council consists of seven Democrats and five Republicans. If a committee of four people is selected, find the probability

Hoochie [10]

Answer:

The probability of selecting two Democrats and two Republicans is 0.4242.

Step-by-step explanation:

The information provided is as follows:

A city council consists of seven Democrats and five Republicans.
A committee of four people is selected.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

${n\choose k}=\frac{n!}{k!\times (n-k)!}$

Compute the number of ways to select four people as follows:

${12\choose 4}=\frac{12!}{4!\times (12-4)!}=495$

Compute the number of ways to selected two Democrats as follows:

${7\choose 2}=\frac{7!}{2!\times (7-2)!}=21$

Compute the number of ways to selected two Republicans as follows:

${5\choose 2}=\frac{5!}{2!\times (5-2)!}=10$

Then the probability of selecting two Democrats and two Republicans as follows:

$P(\text{2 Democrats and 2 Republicans})=\frac{21\times 10}{495}=0.4242$

Thus, the probability of selecting two Democrats and two Republicans is 0.4242.

6 0

2 years ago

39.2 is 95 percent of what?

snow_tiger [21]

267 is what the answer is sorry if it’s wrong

4 0

2 years ago

What are the x-intercepts of the graph of the following function y = 6x to the second power minus 12x - 18

maksim [4K]

Answer:

it would be 12x 26y doe to the problem

7 0

2 years ago

Write the quadratic equation whose roots are -4 and 6 and whose leading coefficient is 3

Svetach [21]

Answer:

y = 3x² - 6x - 72

Step-by-step explanation:

Since the roots are x = - 4 and x = 6 then the factors are

(x + 4) and (x - 6) and the quadratic function is

y = a(x + 4)(x - 6) ← a is a multiplier, in this case 3, so

y = 3(x + 4)(x - 6) ← expand factors and distribute by 3

y = 3(x² - 2x - 24)

y = 3x² - 6x - 72

3 0

2 years ago

Read 2 more answers