The Probability of obtaining no more than two defective tubes in a randomly selected sample of 15 tubes is obtained using the binomial distribution formula: nCr × p^r × q^(n -r).

Where n is number of samples;

r is maximum number of defective tubes, r ≤ 2;

p is probability of defective tubes = 10% or 0.1

q is probability of non-defective tubes, q = 1 - p

Further explanations and calculations are given in the attachment below:

3 0

4 years ago

the sum of two numbers is 35. the smaller number is 21 less than the larger number. What are the numbers?

bearhunter [10]

Answer:

$\huge\boxed{28\ and\ 7}$

Step-by-step explanation:

$x-\text{the bigger number}\\(x-21)-\text{the smaller number}\\35-\text{the sum of numbers}\\x+(x-21)-\text{the sum of numbers}\\\\\text{The equation:}\\\\x+x-21=35\qquad\text{add 21 to both sides}\\\\x+x-21+21=35+21\\\\2x=56\qquad\text{divide both sides by 2}\\\\\dfrac{2x}{2}=\dfrac{56}{2}\\\\x=28\to x-21=28-21=7$