First, I would solve the second parenthesis.

(4xy^3)^2

Distribute

(4^2 x^2 y^6)

4 x 4 = 16

Now, combine like terms

3x^2 x 4x^2 = 12x^4

y^2 x y^6 = y^12

So, the answer would be 12x^4 y^12

Hmm actually I'm not sure. I did this about two years ago so I don't really remember sorry if this is really wrong

5 0

2 years ago

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Use the discriminant to describe the roots of each equation. Then select the best description. 3x2 - 10 = 0. A) Double root B) R

Mademuasel [1]

1. discriminant = b^2 - 4ac = (-5)^2 - (4 x 1 x 7) = 25 - 28 = -3 [imaginary root]

2. discriminant = (-5)^2 - (4 x 1 x -4) = 25 - (-16) = 25 + 16 = 41 [real and irrational root]

3. discriminant = (8)^2 - (4 x 16 x 1) = 64 - 64 = 0 [double root]

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hope it helps

4 0

2 years ago