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Travka [436]
3 years ago
6

Objects in free fall near the surface of the earth accelerate downward at what rate

Physics
2 answers:
N76 [4]3 years ago
3 0
At the rate of 9.8m/s²
approx 10m/s²
Art [367]3 years ago
3 0

Answer:

9.8

Explanation:

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How can a force change the motion of an object that is already moving?
lara [203]

Answer:They may cause motion to change

Explanation:They may cause motion; they may also slow, stop, or change the direction of motion of an object that is already moving. Since force cause changes in the speed or direction of an object, we can say that forces cause changes in velocity. Remember that acceleration is a change in velocity.

7 0
3 years ago
Gauss's law combines the electric field over a surface with the area of the surface. From Coulomb's law we know that the electri
Romashka-Z-Leto [24]

The change in surface area of Gaussian surface with radius (r) is 8πr.

<h3>Electric field from Coulomb's law</h3>

The electric field experienced by a charge is calculated as follows;

E = \frac{Q}{4\pi \varepsilon_o r^2}

where;

  • E is the electric field
  • Q is the charge
  • r is the radius

The electric field reduces by a factor of \frac{1}{r^2}

<h3>Surface area of a Gaussian surface;</h3>

The surface area of a sphere is given as;

A = 4\pi r^2

<h3>Change in area with r</h3>

\frac{dA}{dr} = 8\pi r

Thus, the change in surface area of Gaussian surface with radius (r) is 8πr.

Learn more about area of Gaussian surfaces here: brainly.com/question/17060446

7 0
3 years ago
The impulse experienced by a body is equivalent to the body’s change in?
vovangra [49]
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5 0
4 years ago
A speedometer of a car reads a constant 60 km per hour while negotiating a curve. Which of the following could NOT be true?
seraphim [82]

Answer:

A

Explanation:

3 0
3 years ago
An alternating current is supplied to an electronic component with a rating that the voltage across it can never, even for an in
Vsevolod [243]

Answer:

A) V_{rms}=8\sqrt{2} V

Explanation:

Maximum voltage =V_{max}=16 V

Maximum voltage and rms voltage are related to each other by

V_{max}=V_{rms} \times \sqrt{2} \\V_{rms}=\frac{V_{max}}{ \sqrt{2}}\\V_{rms}=\frac{16}{\sqrt{2}} \\V_{rms}=8\sqrt{2} V

7 0
4 years ago
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