Newton's second law states that the resultant of the forces applied to an object is equal to the product between the object's mass and its acceleration:

where in our problem, m is the mass the (child+cart) and a is the acceleration of the system.
We are only concerned about what it happens on the horizontal axis, so there are two forces acting on the cart+child system: the force F of the man pushing it, and the frictional force

acting in the opposite direction. So Newton's second law can be rewritten as

or

since the frictional force is 15 N and we want to achieve an acceleration of

, we can substitute these values to find what is the force the man needs:
Answer:
Magnetic field, B = 0.0196 T
Explanation:
A current of 0.6 amps flows through a solenoid 6500 turns and 25 cm long. What is the value of the magnetic field inside it?
We have,
Current, I = 0.6 A
Number of turns in the solenoid, N = 6500
Length of solenoid, l = 25 cm = 0.25 m
The magnetic field inside the solenoid is given by :

So, the value of the magnetic field inside the solenoid is 0.0196 T.
Answer:
20 mi
Exp3tanation:
I did the same question in a quizz
Answer:
25.82 m/s
Explanation:
We are given;
Force exerted by baseball player; F = 100 N
Distance covered by ball; d = 0.5 m
Mass of ball; m = 0.15 kg
Now, to get the velocity at which the ball leaves his hand, we will equate the work done to the kinetic energy.
We should note that work done is a measure of the energy exerted by the baseball player.
Thus;
F × d = ½mv²
100 × 0.5 = ½ × 0.15 × v²
v² = (2 × 100 × 0.5)/0.15
v² = 666.67
v = √666.67
v = 25.82 m/s