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laila [671]
3 years ago
12

Which of the following is the most likely global climate change?a.a decrease in the overall temperature of the Earthb.an increas

e in the overall temperature of the Earthc.an increase in the number of cold climatesd.no change to global climate
Physics
2 answers:
mr_godi [17]3 years ago
7 0

Due to the increase in the greenhouse gases emission, the ability to trap the heat in the atmosphere has increased. Due to which the global warming on the earth has increased. Due to the trapping of the heat, the average temperature everywhere has increased.

Hence, the answer is: An increase in the overall temperature of the earth.

andrew11 [14]3 years ago
5 0
I believe the answer is C. an increase in the number of cold climates
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A plane monochromatic radio wave (? = 0.3 m) travels in vacuum along the positive x-axis, with a time-averaged intensity I = 45.
Mariana [72]

Answer:

The magnetic field B_Z = - 6.14*10^{-7} T

Explanation:

From the question we are told that

      The wavelength is \lambda = 0.3m

       The intensity is I = 45.0W/m^2

       The time is t = 1.5ns = 1.5 *10^{-9}s

Generally radiation intensity is mathematically represented as

              I = \frac{1}{2} c \epsilon_o E_o^2

Where  c is the speed of light with a constant value of 3.0 *10^8 m/s

              E_i is the electric field

             \epsilon_o is the permittivity  of free space with a constant value of 8.85*10^{-12} C^2 /N \cdot m^2

 Making E_o the subject of the formula we have

           E_i = \sqrt{\frac{2I}{c \epsilon_0} }

      Substituting values

          E_i = \sqrt{\frac{2* 45 }{(3*10^8 * (8.85*10^{-12}) )} }

               = 184.12 \ V/m

Generally electric and magnetic field are related by the mathematical equation as follows

             \frac{E_i}{B_i} = c

Where B_O is the magnetic field

           making  B_O the subject

                 B_i = \frac{E_i}{c}

Substituting values

                 B_i = \frac{184.12}{3*10^8}

                       = 6.14 *10^{-7}T

Next is to obtain the wave number

  Generally  the wave number is mathematically represented as

                          n = \frac{2 \pi }{\lambda }

Substituting values

                          n = \frac{2 \pi}{0.3}

                              = 20.93 \ rad/m

Next is to obtain the frequency

      Generally  the  frequency f is mathematically represented as

                    f = \frac{c}{\lambda}

Substituting values

                   f = \frac{3 *10^8}{0.3}

                      = 1*10^{9} s^{-1}

Next is to obtain the angular velocity

                Generally  the  angular velocity  w is mathematically represented as

                       w = 2 \pi f

                           w = 2 \pi (1* 10^9)

                              = 2 \pi * 10^9 rad/s

Generally  the sinusoidal electromagnetic waves for the magnetic field B moving in the positive z direction is expressed as

                       B_z = B_i cos (nx -wt)

Since the magnetic field is induced at the origin then the equation above is reduced to

                   B_z = B_i cos (n(0) -wt) =  B_i cos ( -wt)

x =0 because it is the origin we are considering

 Substituting values  

                      B_z = (6.14*10^{-7}) cos (- (2 \pi * 10^{9})(1.5 *10^{-9}))

                           = - 6.14*10^{-7} T

3 0
3 years ago
A barge floating in fresh water (rho = 1000 kg/m3) is shaped like a hollow rectangular prism with base area A = 550 m2 and heigh
lapo4ka [179]

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8 0
3 years ago
An experimental rocket designed to land upright falls freely from a height of 2.59 102 m, starting at rest. At a height of 86.9
aleksandr82 [10.1K]

Answer:

The acceleration required by the rocket in order to have a zero speed on touchdown is 19.96m/s²

The rocket's motion for analysis sake is divided into two phases.

Phase 1: the free fall motion of the rocket from the height 2.59*102m to a height 86.9m

Phase 2: the motion of the rocket due to the acceleration of the rocket also from the height 86.9m to the point of touchdown y = 0m.

Explanation:

The initial velocity of the rocket is 0m/s when it started falling from rest under free fall. g = 9.8m/s² t1 is the time taken for phase 1 and t2 is the time taken for phase2.

The final velocity under free fall becomes the initial velocity for the accelerated motion of the rocket in phase 2 and the final velocity or speed in phase 2 is equal to zero.

The detailed step by step solution to the problems can be found in the attachment below.

Thank you and I hope this solution is helpful to you. Good luck.

5 0
3 years ago
A simple harmonic oscillator of amplitude A has a total energy E.
jeka57 [31]

Answer:

a) K=E-\frac{kA^2}{18}

b) U=\frac{kA^2}{18}

Explanation:

The law of conservation of mechanical energy states that total mechanical energy remains constant during oscillation. Mechanical energy is defined as the sum of kinetic energy and potential energy:

E=U+K\\E=\frac{kx^2}{2}+\frac{mv^2}{2}

a) The position is one-third the amplitude. So, we have x=\frac{1}{3}A. Replacing and solving for K

E=\frac{k(\frac{1}{3}A)^2}{2}+K\\E=\frac{kA^2}{18}+K\\K=E-\frac{kA^2}{18}

b) The potential energy is defined as:

U=\frac{kx^2}{2}

Replacing:

U=\frac{k(\frac{1}{3}A)^2}{2}\\U=\frac{kA^2}{18}

4 0
3 years ago
Can someone help me with one through seven I will mark you the brainly
ki77a [65]

Answer:

1.  F = M x A

2. Force  

3. 2nd Law: Force

4. a, b, c (in order)

5. 3rd Law: Action and Reaction

6. b, c, a (in order)

7. 1st Law: Inertia

3 0
3 years ago
Read 2 more answers
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