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kondaur [170]
2 years ago
9

A cobalt atom contains 27 protons, 32 neutrons, and 27 electrons. What is

Physics
1 answer:
kirza4 [7]2 years ago
3 0
32? I could be wrong but I’m going with that answer choice
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Someone please answer this, ill give you brainliest and your earning 50 points.
Tema [17]

All of the following are non-renewable resources except

O natural gas

O oil

O minerals

O <em>water ✓ </em>

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3 0
1 year ago
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A wrench is accidentally dropped at the top of an elevator shaft in a tall building. (a) How many meters does the wrench fall in
RUDIKE [14]

Answer:

11.25m

Explanation:

s = ut +  \frac{1}{2} a {t}^{2}  \\  = 0 \times 1.5 +  \frac{1}{2} \times 10 \times   {1.5}^{2}  \\  = 5 \times 2.25 \\  = 11.25

6 0
3 years ago
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PtichkaEL [24]

Answer:

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Explanation:

6 0
3 years ago
A rotating wheel requires 5.00 s to rotate 28.0 revolutions. Its angular velocity at the end of the 5.00-s interval is 96.0 rad/
torisob [31]

Answer:

The constant angular acceleration of the wheel is 12.16 rad/s²

Explanation:

Given;

initial angular distance, θ = 28

time of the motion, t = 5 s

initial angular velocity is calculated as;

\omega _i = \frac{\theta}{t} = \frac{28}{5}.\frac{rev}{s}  \ \times \ \ \frac{2 \pi \ rad}{1 \ \ rev} = 35.19 \ rad/s

final angular velocity is given as, \omega _f = 96.0 \ rad/s

The constant angular acceleration is calculated as;

\alpha = \frac{\omega _f - \omega _i}{t} \\\\\alpha = \frac{96 - 35.19}{5} \\\\\alpha =  12.16 \ rad/s^2

Therefore, the constant angular acceleration of the wheel is 12.16 rad/s²

6 0
3 years ago
A graduated cylinder contains 63.0 mL of water. A piece of gold, which has a density of 19.3 g/ cm3, is added to the water and t
icang [17]

Answer:

29.0 g

Explanation:

The mass of the piece of gold is given by:

m = dV

where

m is the mass

d is the density

V is the volume of the piece of gold

The density of gold is

d = 19.3 g/cm^3

while the volume of the sample is equal to the volume of displaced water, so

V = 64.5 mL - 63.0 mL = 1.5 mL

And since

1 mL = 1 cm^3

the volume is

V = 1.5 cm^3

So the mass of the piece of gold is:

m = (19.3 g/cm^3)(1.5 cm^3)=29.0 g

7 0
3 years ago
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