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Rama09 [41]
3 years ago
10

1) If you borrow $120,000 at an APR of 7% for 25 years, you will pay $848.13 per month. If you

Mathematics
1 answer:
Arlecino [84]3 years ago
5 0

Step-by-step explanation:

If you borrow $120,000 at an APR of 7% for 25 years, you will pay $848.13 per month. If you

borrow the same amount at the same APR for 30 years, you will pay $798.36 per month.

a. What is the total interest paid on the 25-year mortgage? <em>$134,439.</em>

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The points (–5, 6) and (5, 6) are vertices of a hexagon. The line segment joining the two points forms one of the sides of the h
xxTIMURxx [149]

The information about the points being vertices that make up a line to represent the side of a hexagon is irrelevant, as we are only looking for the distance of a line based on their x and y coordinates.

Look at the point's x and y coordinates:

First point:

x = -5, y = 6

Second point:

x = 5, y = 6

You'll notice that the y-coordinate for both points is the same (6 = 6). This means that the segment created by the points will be horizontal, since there is only movement on the x-axis if you trace the segment from point to point.

To find the distance between the two points, we'll only need to subtract the first point's x-coordinate from the second:

5 - (-5) = 5 + 5 = 10

The answer will be the following statement:

Since the y-coordinates are the same, the segment is horizontal, and the distance between the points is 10 units.

5 0
3 years ago
Read 2 more answers
What is the domain of the function?
Fiesta28 [93]

Answer:

c. 0,100

Step-by-step explanation:

4 0
3 years ago
Need help simplifying this
diamong [38]

The simplified answer is \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}.

<u>Step-by-step explanation:</u>

$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term (\frac{3x+y}{3x+y}) and 2nd term by (\frac{z+2x}{z+2x})

= \frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= \frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}

Now, the denominators are same, you can subtract it.

= \frac{\left(6 x^{2}+6 x^{2}+11 x y-4 x y-2 y z-2 y z+3 x z-6 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

= \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

Thus the simplified solution is  \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

4 0
3 years ago
Commutative Property of Addition<br><br> 25 + (-x) =
creativ13 [48]

Answer:

x is 25

Hope it helps.....

3 0
3 years ago
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The statement is either true in all cases or false. If false, construct a specific example to show that the statement is not alw
natali 33 [55]

Answer: The correct option is (B).

True. The vector V₃ is a linear combination of V₁ and V₂, so at least one of the vectors in the set is a linear combination of the others and set is linearly dependent.  

Step-by-step explanation:  

Given that;

If V₁ ....... V₄ are in R⁴ and V₃ = 2V₁ + V₂ then {V₁, V₂, V₃, V₄} is linearly dependent.  

Lets {V₁, V₂, V₃, V₄}  are linearly dependent

Then there exist a scalars C₁, C₂, C₃, C₄

So that C₁V₁ + C₂V₂ + C₃V₃ + C₄V₄ = 0

where at least one of the Ci ≠ 0.  

Take C₃ ≠  0 then we have V₃ = (C₁V₁ + C₂V₂ + C₄V₄) / C₃

V₃ is a linear combination of V₁, V₂ and V₄}

that is

Given V₃ = 2V₁ + V₂

⇒ 2V₁ + V₂ - V₃ = 0

⇒ 2V₁ + V₂ + V₃ + 0V₃ = 0

Here, C₁ = 1, C₂ = 1,  C₃ = -1 and C₄ = 0

So that {V₁, V₂, V₃, V₄} is linearly dependent.

therefore option B id the right answer.

- True. The vector V₃ is a linear combination of V₁ and V₂, so at least one of the vectors in the set is a linear combination of the others and set is linearly dependent.  

4 0
3 years ago
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