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stepladder [879]
3 years ago
5

Domain and Range functions

Mathematics
1 answer:
Iteru [2.4K]3 years ago
5 0
Interval notation or standard?
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325/48=# of busses
7 busses
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What are the roots of this equation?
Katyanochek1 [597]

Answer:

x = 2 ± (i)√5  (Answer b)

Step-by-step explanation:

x²-4x+9=0 can be solved in a variety of ways; the first two that come to mind that are also appropriate are (1) completing the square and (2) using the quadratic formula.

Completing the square is fast here:

Rewrite x²-4x+9=0 as   x²-4x                    +9=0

Identify the coefficient of the x term:  it is -4

Take half of that, obtaining -2

Square this result, obtaining 4

Add 4 to   x²-4x                    +9=0, in the blank space in the middle, and then subtract 4:      x²-4x +4          -4         +9=0

Rewrite           x²-4x +4 as the square of a binomial:

                          (x - 2)² - 4 + 9  = 0  →    (x - 2)²  = -5

Take the square root of both sides:       x - 2  = ±√(-5)  =  ± (i)√5

Then x = 2 ± (i)√5

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2 years ago
What is the solution of 3|x – 5| + 2 = 20?
ziro4ka [17]
X=11,-1 is the right answer
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3 years ago
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What is the area of a regular hexagon with an apothem 18.5 inches long and a side 21 inches
earnstyle [38]

The area of a regular hexagon with an apothem 18.5 inches long and a side 21 inches is 1, 165. 5 In²

<h3>How to calculate the area of a regular hexagon</h3>

The formula is given thus;

Area of hexagon = (1/2) × a × P

where a = the length of the apothem

P = perimeter of the hexagon

Given a = 18. 5 inches

Note that Perimeter, p = 6a with 'a' as side

p = 6 × 21 = 126 inches

Substitute values into the formula

Area, A = 1 ÷2 × 18. 5 × 126 = 1 ÷2 × 2331 = 1, 165. 5 In²

Thus, the area of the regular hexagon is 1, 165. 5 In²

Learn more about the area of a hexagon here:

brainly.com/question/15424654

#SPJ1

3 0
1 year ago
Which relation is also a function? A, B, C, or D?
andrew-mc [135]

Answer:

AorD

srry if im wrong its not B because some of them are not compatible

Step-by-step explanation:

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