Answer:
Α. 0
Step-by-step explanation:
Given A = -8 and B = 10
The distance between A and B
= B - A
= 10 - (-8)
= 10 + 8
= 18 units
4/9 of the way between A and B
= 4/9 of the distance between A and B
= 4/9 x 18 units
= 8 units.
Hence the location of the point that is 4/9 of the way from A to B
= value at point A + 8 units
= -8 + 8
= 0 (answer)
Answer:

Step-by-step explanation:
We can use formula (a-b)² = a² -2ab + b².
In our example a = 3c^4 and b = 5c^6
![(3c^{4} - 5c^{6})^{2} = [3c^{4} ]^{2} - 2*3c^{4} *5c^{6} + [5c^{6}]^{2}=\\=9c^{8} -30c^{10} + 25c^{12}](https://tex.z-dn.net/?f=%283c%5E%7B4%7D%20-%205c%5E%7B6%7D%29%5E%7B2%7D%20%3D%20%5B3c%5E%7B4%7D%20%5D%5E%7B2%7D%20-%202%2A3c%5E%7B4%7D%20%2A5c%5E%7B6%7D%20%2B%20%5B5c%5E%7B6%7D%5D%5E%7B2%7D%3D%5C%5C%3D9c%5E%7B8%7D%20-30c%5E%7B10%7D%20%2B%2025c%5E%7B12%7D)
8x(5x2+3)=8x(15+3)=8x13=104
Answer: the answers are below
Step-by-step explanation:
1 meal = 2/3 of a can of wet dog food, 1/8 of a bag of dry dog food, and 3/5 a patty of special meat
Food for 1 day: 2 meals = 2(2/3) = 4/3 of a can of wet dog food, 2(1/8) = 1/4 of a bag of dry dog food, and 2(3/5) = 6/5 a patty of special meat
The trainer goes to the store and buys 24 cans of wet food, 4 bags of dry food and 3 packages of meat (3*6 = 18 patties)
He has:
there is wet food for: 24/(4/3) = 24*3/4 = 18 days
there is dry food for: 4/(1/4) = 4*4 = 16 days
there is special meat food for: 18/(6/5) = 18*5/6 = 15 days
since the minimum for 15, 16 and 18 is 15 the dog will have food for 15 days and first he will run out of special meat.
Answer:
in my ipinion...
Step-by-step explanation:
let a no.be x
1/3*x+77=33
1/3*x=-44
x=-44*3
x=-132