How many enantiomeric pairs are possible for an aldohexose? a.2 b.4 c.8 d.16?
2 answers:
Based on this question, one thing that we would seriously consider would be the fact of first, doing 
first. By doing this, it would then give us our answer as 16. By us understanding this point of view, we would then consider that this would then be your answer. That would then include that there would then be 16 pairs of the "enantiomeric pairs", and that would then be the possible estimate.
<span>a.2
b.4
c.8
d.16</span>
<span>a.2
b.4
c.8
d.16</span>
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Answer:
84.38% probability that he succeeds on at least two of them
Step-by-step explanation:
For each free throw, there are only two possible outcomes. Either Giannis makes it, or he does not. The free throws are independent. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
He has a 3/4 probability of success.
This means that
Giannis shoots three free throws
This means that
What is the probability that he succeeds on at least two of them
84.38% probability that he succeeds on at least two of them
Answer:
a) 0.8413
b) 421
c)
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 165
Standard Deviation, σ = 15
We are given that the distribution of IQ examination scores is a bell shaped distribution that is a normal distribution.
Formula:
a) P(IQ scores at most 180)
P(x < 180)
Calculation the value from standard normal z table, we have,
b) Number of the members of the club have IQ scores at most 180
n = 500
c) P(X< x) = 0.95
We have to find the value of x such that the probability is 0.95
Calculation the value from standard normal z table, we have,