Answer:
there ARE NO AXES
Step-by-step explanation:
Answer: y = ![-\frac{1}{6}x-5](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B6%7Dx-5)
Step-by-step explanation:
x+6y=12
6y=-x+12
y=-
+ 2
If its parallel it means that the slope will be the same
y = mx + b
-4 = -1/6 * (-6) + b
b = -5
Thus,
y = -1/6 x - 5
Answer
Find out the area of the running track that goes around the field .
To proof
Formula
Area of rectangle = length× breadth
![Area\ of\ semi-circle = \frac{1}{2}\pi r^{2}](https://tex.z-dn.net/?f=Area%5C%20of%5C%20semi-circle%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Cpi%20r%5E%7B2%7D)
![\pi =3.14](https://tex.z-dn.net/?f=%5Cpi%20%3D3.14)
area of running track = outside area - inside area
First case ( outside )
length = 73 + 2 × 9.76
= 92.52m
Breadth = 84.39 m
radius of outside semi circle
![= \frac{92.52}{2}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B92.52%7D%7B2%7D)
=46.26m
outside area = area of rectangle + 2× area of the semi- circle
= 92.52× 84.39 + 3.14× 46.26 ×46.26
= 7807.76+ 6719.56
= 14527.32 m² ( approx)
Second case
radius of the semi- circle
![= \frac{73}{2}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B73%7D%7B2%7D)
=36.5m
inside area = area of rectangle + 2× area of the semi- circle
= 73× 84.39 + 3.14× 36.5 ×36.5
= 6160.47 + 4183.27
= 10343.74m²
area of running track= 14527.32 m² - 10343.74m²
= 4183.58m²
Hence proved
Answer:
The statement is true.
Step-by-step explanation:
Given : Reflecting the graph of y = sin x across the y-axis is the same as reflecting it across the x-axis.
To find : Is this statement true or false?
Solution:
Rules of reflection :
Along across y-axis if we have a point
So, y=sinx
The reflection across y-axis→ .......[1]
Along across x-axis if we have a point
so, y=sinx
The reflection across x-axis → .....[2]
Hence, [1] and [2] both of them are equal
Therefore, the statement is true.
N=-1 I think this is right gl