Answer:
A and E
Step-by-step explanation:
Given
Graphs A to E
Required
Which do not have solutions
When there are no point of intersection between lines and/or curves of a graph, then such graph has no solution.
Using the above description as a yard stick, the first (A) and the last (E) graph have no solution.
i think the answer would be C
Answer: 8n
Let's simplify step-by-step.
(2(n+1)−1)2−(2n−1)2
Distribute:
=4n2+4n+1+−4n2+4n+−1
Combine Like Terms:
=4n2+4n+1+−4n2+4n+−1
=(4n2+−4n2)+(4n+4n)+(1+−1)
=8n
Answer:
32 ÷ 8 + 1 __IS NOT EQUAL TO__ 3² - 1
4² __IS NOT EQUAL TO__ 4 • 2
3(x - 4 + x) __IS EQUAL__ 3x - 4 + x
when x = 4
15 ÷ (1 + 2) ___IS NOT EQUAL TO_ 15 ÷ 1 + 2
3(x - 4 + x) __IS NOT EQUAL TO__ 3x - 4 + x
when x = 2
Answer:
19y - 9
Step-by-step explanation:
We can use the acronym PEMDAS. First, we need to calculate -3(-4y+3) by distributing. This is -3 * (-4y) + (-3) * 3 = 12y - 9 so the expression becomes 12y - 9 + 7y. Next, we need to combine like terms. 12y and +7y are like terms since they both have y so combining them gives us 12y + 7y = 19y. -9 stays by itself since there are no other constants so the final answer is 19y - 9.
