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Dmitrij [34]
3 years ago
7

The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop

machines and the other four have chosen desktop machines. Suppose that only two of the setups can be done on a particular day, and the two computers to be set up are randomly selected from the six (implying 15 equally likely outcomes; if the computers are numbered 1, 2, ..., 6, then one outcome consists of computers 1 and 2, another consists of computers 1 and 3, and so on).
a. What is the probability that both selected setups are for laptop computers?
b. What is the probability that both selected setups are desktop machines?
c. What is the probability that at least one selected setup is for a desktop computer?
d. What is the probability that at least one computer of each type is chosen for setup?
Mathematics
1 answer:
marta [7]3 years ago
3 0

Answer:

At the U.S. Open Tennis Championship a statistician keeps track of every serve that a player hits during the tournament. The statistician reported that the mean serve speed of a particular player was 95 miles per hour. Suppose that the statistician indicated that the serve speed distribution was skewed to the left. Which of the following values is most likely the value of the median serve speed? Explain your answer.

Step-by-step explanation:

At the U.S. Open Tennis Championship a statistician keeps track of every serve that a player hits during the tournament. The statistician reported that the mean serve speed of a particular player was 95 miles per hour. Suppose that the statistician indicated that the serve speed distribution was skewed to the left. Which of the following values is most likely the value of the median serve speed? Explain your answer.

a. What is the probability that both selected setups are for laptop computers?

b. What is the probability that both selected setups are desktop machines?

c. What is the probability that at least one selected setup is for a desktop computer?

d. What is the probability that at least one computer of each type is chosen for setup?

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Write the function in standard form <br><br> F(x)=-3(x-6)^2+15
LenKa [72]

Answer:

(6,15)

Step-by-step explanation:

7 0
3 years ago
2x-1<br> Evaluate the algebraic expressions for the given values of the variable
igor_vitrenko [27]
<span>An algebraic expression is an expression constructed from a number of constants and variables utilizing algebraic operations. These algebraic operations are addition, subtraction, multiplication, division, and exponentiation. A constant is constant, so its value is unchanged. A variable changes based on the value provided. In the provided example, 2x-1, there are two constants, "2" and "1", and one variable "x." The algebraic operations utilized are multiplication and subtraction. In order to evaluate the value of the algebraic expression, the given value for the variable must be substituted for the variable x, and then the algebraic operations executed to obtain the answer. For instance, if you were told that the value of x in this case was 2, then you would substitute the value 2 for x and perform the described operations. Remember to follow the order of operations when evaluating an algebraic expression! 2x-1 for x=2 2(2) - 1 4 - 1 3 is the answer. Remember, even though the multiplication operation is not explicitly stated, it is implied that a constant attached to a variable (termed a coefficient) is multiplied with the value of the variable.</span>
5 0
3 years ago
You cross two true-breeding parents (one with purple flowers and one with white flowers). All of the F1 progeny (offspring) have
kogti [31]

Answer:

The correct answer is 375 purple flowers.

Step-by-step explanation:

If all the F1 generation from true-breeding parents are purple than the genotype would be heterozygous i.e., Pp and Pp. Here P indicates the dominant allele which produces purple flower and p indicates the recessive allele of white flower.

So if we will cross the F 1 generation than the genotype would be PP, Pp, Pp, pp. That means 3 out of 4 offspring would be purple because three genotypes out of four have dominant purple allele(P).

So if out of 4 flower 3 is purple than according to calculation out of 500 flower 375 offspring would be purple(3/4*500= 375). Therefore the correct answer is 375 purple flowers should be produced.

7 0
3 years ago
What is the arithmetic sequence in this problem . help plz
adell [148]

Answer:

<u>a(n)=80*(9/10)^(n-1)</u>

Step-by-step explanation:

I think u r confused

this sequence is geometric not arithmetic

HOw we know that ??

when we get a common difference  <u>that must Be equal  </u>

d=72-80=-8  not equal to  d=64.8-72=-7.2

So it is not arithmetic

but when we get the common ratio that also must <u>be equal </u>

r=72/80=9/10 equal to   r=64.8/72=9/10

So it is geometric

By using this equation:

a(n)=a*r^(n-1)

and we have <u>a=80 , r=9/10</u>

Then       <u>a(n)=80*(9/10)^(n-1)</u>

<em>I really hope this helps <3</em>

6 0
3 years ago
Y varies directly with x, and y = 5 when x = 4. What is the value of x when y = 8
ollegr [7]
10
x equals 10
5 times 2 


7 0
3 years ago
Read 2 more answers
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