Answer:
The expression
gives the amount the plant earned per a man-hour of labor 3 years after it opened.
Step-by-step explanation:
Given:
Amount earned by Manufacturing Plant = $80/per man -hour labor
Percent increase in Amount earned by Manufacturing Plant each year = 6%
We need to find the expression gives the amount the plant earned per a man-hour of labor 3 years after it opened.
Solution:
Now we will use the expression;
![y(t)=a(1+r)^t](https://tex.z-dn.net/?f=y%28t%29%3Da%281%2Br%29%5Et)
Where;
⇒ Amount after t years
⇒ Initial amount
⇒ rate of change in amount
⇒ Amount of time
In The given data;
![y(t) =A(t)](https://tex.z-dn.net/?f=y%28t%29%20%3DA%28t%29)
![a=80](https://tex.z-dn.net/?f=a%3D80)
![r= 6\% =\frac{6}{100}=0.06](https://tex.z-dn.net/?f=r%3D%206%5C%25%20%3D%5Cfrac%7B6%7D%7B100%7D%3D0.06)
t = ![3\ years](https://tex.z-dn.net/?f=3%5C%20years)
So we can say that;
![A(t)= 80(1+0.06)^t=80(1.06)^t](https://tex.z-dn.net/?f=A%28t%29%3D%2080%281%2B0.06%29%5Et%3D80%281.06%29%5Et)
To find the amount the plant earned per a man-hour of labor 3 years after it opened we will substitute the value of t as 3.
![A(3) =80(1.06)^3](https://tex.z-dn.net/?f=A%283%29%20%3D80%281.06%29%5E3)
Hence The expression
gives the amount the plant earned per a man-hour of labor 3 years after it opened.
I’m going to assume the periods represent multiplication signs.
-7x9x-1= 63
-3x-5x-3= -45
4x8x-2= -64
hope this helps!
2×3=6
6×1=6
12÷2=6
Sorry if these don't help.
Answer: C
Step-by-step explanation:
(5x^2 - 2x + 14) - (x^2 + 4x - 10)
4x^2 - 6x + 24
Let the <span> normal hourly rate be x
so normal wages = 40x
bonus = 1.5x(52-40) = 18x
total = 40x+18x =58x = $638.
x = $11/hour</span>