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katrin2010 [14]
3 years ago
11

The game of monopoly has 4 railroad properties 2 utility properties 2 properties each of dark purple and dark blue and 3 propert

ies each of light blue pink orange red yellow and green what is the probability of NOT selecting a railroad property from the stack of property cards?

Mathematics
1 answer:
vova2212 [387]3 years ago
6 0
4/18 = 0.22 reoccurring
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The rectangular area measures 30 ft by 25ft. The fencing that will be used comes in 25 ft sections. How many sections will you n
lbvjy [14]

Answer:

5

Step-by-step explanation:

8 0
3 years ago
Kurt says factors and multiples are
maxonik [38]

<u>Step-by-step Explanation:</u>

<em>Before heading towards the solution, you need to make sure how multiple and factors are related to each other.</em>

<em>The multiple of a number could be obtained by multiply it with another number. </em>

For example, the first five multiples of 12 are 12, 24, 36, 48 and 60

  • 1 X 12 = 12
  • 2 X 12 = 24
  • 3 X 12 = 36
  • 4 X 12 = 48
  • 5 X 12 = 60

<em>Factors are the numbers that are multiplied to get a given number.</em>

For example,

  • 1 X 12 = 12
  • 2 X 12 = 24
  • 3 X 12 = 36

The factors of 12 are 1, 2, 3, 4, 6 and 12.

As division and multiplication can be used to find factors and multiples.

For example a whole number is a multiple of its factors.

Let w = {2, 4, 6, 8, 10, 12, 14, 16, 18, 20} be the set of even wholes numbers from 2 to 20.

As 2 is a factor of 20 because 20 ÷ 2 = 4

20 is a multiple of 2 because 2 X 10 = 20

So, in the same way, the equation 8 X 5 = 40 can be used to determine how factors and multiples are related.

Let the equation be

                                    8 X 5 = 40

8 is a factor of 40 because 8 X 5 = 40

40 is a multiple of 8 because 40 ÷ 5 = 8

<em>So, this is how factors and multiples are related to each other.</em>

<em />

<em>Keywords: factors, multiples, division, multiplication</em>

<em> Learn more about factors and multiples from brainly.com/question/596356</em>

<em> #learnwithBrainly</em>

4 0
3 years ago
If x° – 7x2 + kx + 15 is exactly divisible by (x – 3), then find the value of k.​
faltersainse [42]

Answer:

k=4

Step-by-step explanation:

3 0
2 years ago
What is the equation of the line that passes through the point (4.11) and is perpendicular to the line with the following equati
ollegr [7]

Answer:

the answer is A ..............

8 0
2 years ago
The quality-control department of Starr Communications, the manufacturer of video-game cartridges, has determined from records t
notsponge [240]

Answer: (A) The probability that a cartridge purchased will have a video or audio defect is 1.9%

(B) The probability that a cartridge purchased will not have a video or audio defect is zero.

Step-by-step explanation: The data given shows that 1.2% (or 120) cartridges have video defects, 0.9% have audio defects (or 90) and 0.2% (or 20) have both audio and video defects.

The possible outcomes for all events (audio defects and video defects) is derived as 120 plus 90 which is equals 210 possibilities (or possible outcomes).

Therefore the probability of having an audio defect is calculated as follows;

P(Audio) = Number of required outcomes/Number of all possible outcomes

P(Audio) = 90/210

P(Audio) = 3/7

Also the probability of having a video defect is derived as follows;

P(Video) = Number of required outcomes/Number of all possible outcomes

P(Video) = 120/210

P(Video) = 4/7

However we should take note of the fact that 0.2% or 20 of the cartridges in the sample size has both audio and video defects. Hence the probability that a cartridge has both audio and video defects is calculated as;

P(Audio and Video) = Number of required outcomes/Number of all possible outcomes

P(Audio and Video) = 20/210

P(Audio and Video) = 2/21

To calculate the probability that a cartridge bought would have either an audio or a video defect would mean to add both probabilities together, but we MUST SUBTRACT the probability of having both an audio defect and video defect (that is P{Audio and Video}). The reason is that this is already included in both probabilities and we need to avoid double counting. Hence we have;

(A); P(Video OR Audio defect) = P(Audio) + P(Video) - P(Audio and Video)

P(Video OR Audio defect) = (3/7 + 4/7) - 2/21

P(Video OR Audio defect) = 1 - 2/21

P((Video OR Audio defect) = 19/21

Therefore the probability that a cartridge purchased will have a video or audio defect is 190, or better still 1.9%.

(B): From all possibilities shown, which is 210 possibilities of either events, we have determined that 120 will be the probability of having an audio defect and 90 will be the probability of having a video defect. Therefore the probability that a cartridge purchased will not fall into any of either possibilities is zero.

6 0
3 years ago
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