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FinnZ [79.3K]
4 years ago
13

An empty capacitor is capable of storing 1.0 × 10-4 J of energy when connected to a certain battery. If the distance between the

plates is halved and then filled with a dielectric (κ = 4.3), how much energy could this modified capacitor store when connected to the same battery?
Physics
1 answer:
dangina [55]4 years ago
3 0

Answer:

Explanation:

Energy stored in a capacitor

= 1/2 C₁V²

capacity of a capacitor

c = εK A / d

k is dielectric and d is distance between plates .

When  the distance between the plates is halved and then filled with a dielectric (κ = 4.3)

capacity becomes 4.3  x 2 times

New capacity

C₂ = 8.6 C₁

Energy of modified capacitor

1/2 C₂ V²= 1/2 x 8.6 c x V²

Energy becomes

8.6 times.

Energy stored = 8.6 x 10⁻⁴ J

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The way the sound waves hit your eardrums and they are moved by the sound pressure. Then your brain takes over from there.
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Find the average braking force of a 1000 kg car moving at 10 m/s braking to a stop in 5 s.
Verdich [7]

Answer:

-2000 N

Explanation:

To solve the problem, we can use the impulse theorem, which states that the impulse is equal to the change in momentum of the car:

I = \Delta p\\F \Delta t = m \Delta v

where

F is the average breaking force

\Delta t = 5 s is the stopping time

m = 1000 kg is the mass of the car

\Delta v = -10 m/s is the change in velocity of the car

Solving the equation for F,

F=\frac{m \Delta v}{\Delta t}=\frac{(1000 kg)(-10 m/s)}{5 s}=-2000 N

5 0
4 years ago
One positve and one negative charhe jave a force of -5. 00 N between them. If the force changed to -170 N , by what factor did t
stepladder [879]

Answer:

The distance is shortenend by factor .1715

Explanation:

5 n  = 1/r^2

sqrt (1/5) = r

170 n  = 1 / ( x sqrt(1/5))^2

(xsqrt 1/5)^2 = 1/170

x sqrt 1/5  = .076696

x = .1715    

5 0
2 years ago
Expressing Experimental Error If the accepted value of π is 3.1416, what are the fractional error and the percent error of the e
LUCKY_DIMON [66]

Answer:

1) Δx  = 0.16 m / s² ,   Δx = 9.72-9.8 = 0.08 m / s²

2)  e% = 1.63% , ,   e% = 0.816%

3)           1e% = 0.04

Explanation:

The fractional error in a quantity is the absolute error between the accepted value of the quantity and the percentage error is the fractional error per 100

In this case, it is not indicated which is the measured experimental value of pi, suppose that a value of 3.142 is measured

fractional error

                 e = (ax - ax_average) / x_average

                 e = (3.142 - 3.1416) / 3.1416

                 e = 1.27 10⁻⁴

the percentage error is

                 % = e 100

                 % = 1.27 10-4 100

                 % = 1.27 10⁻²%

1) Δx = 9.96-9.8 = 0.16 m / s²

            Δx = 9.72-9.8 = 0.08 m / s²

2) the percentage difference

 x = 9.96 m / s2

             e% = (9.96 - 9.80) / 9.80 100

             e% = 1.63%

x = 9.72 m / s2

             e% = (9.72 -9.80) / 9.80 100

              e% = 0.816%

3) the mean value is

                x_average = (x1 + x2) / 2

               x_average = (9.96 + 9.72) / 2

               x_average = 9.84 m / s2

               e% = (9.84 - 9.80) / 9.80 100

             1e% = 0.04

7 0
3 years ago
An object moving with constant acceleration near the surface of the earth
ziro4ka [17]
The answer is C because if it’s moving with a constant speed it’s gonna be balanced and there will be no force
6 0
3 years ago
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