Answer:
(a) Z = 48.3 Ω
(b) cos ∅ = 0.455
(c) Irms = 10.35 A
(d) C = 74.02 μF
(e) Irms = 4.44 A
Explanation:
Power (P) = 2.36 kW
Frequency (f) = 50 Hz
RMS Voltage (Vrms) = 500 V
Resistance (R) = 22 Ω
Inductive Reactance (XL) = 43 Ω
(a) to calculate the total impedance, use the formula:
Z = √(R² + XL²)
= √((22)² + (43)²)
= √2333
Z = 48.3 Ω
(b) To calculate the plant's power factor, we will use the formula:
cos ∅ = R/Z
= 22/48.3
cos ∅ = 0.455
(c) To calculate the RMS current used by the plant, divide the RMS voltage value by the impedance of the plant.
Irms = Vrms/Z
= 500/48.3
Irms = 10.35 A
(d) For the power factor to become unity, the inductive reactance must be equal to the capacitive reactance i.e. Xc = XL
Xc = XL
1/(2πfC) = XL
1/(2πfXL) = C
C = 1/(2π*50*43)
= 7.402 x 10⁻⁵
C = 74.02 μF
(e) P = Vrms*Irms*cos∅
Irms = P/Vrms*cos∅
= 2.22 x 10³/500*1
Irms = 4.44 A
Answer:
7 Newton
Explanation:
Dado
Longitud de la cuerda = 50 m
El cable se dobla en 0,058 m.
Masa de roedor = 350 gramos = 0,35 kg
T = m * a + m × v2 / r
Sustituyendo los valores dados obtenemos
T = 0,35 (10 + 10)
T = 0,35 * 20
T = 7 Newton
Answer:
Radius, r = 0.00523 meters
Explanation:
It is given that,
Magnetic field, 
Current in the toroid, I = 9.6 A
Number of turns, N = 6
We need to find the radius of the toroid. The magnetic field at the center of the toroid is given by :

r = 0.00523 m
or

So, the radius of the toroid is 0.00523 meters. Hence, this is the required solution.
No. Mechanical energy is not conserved. There's quite a bit of friction on the slide. So some of the potential energy is lost to heat on the way down, and the child arrives at the bottom with hot pants and less kinetic energy than you might expect.