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just olya [345]
2 years ago
15

Pls help me solve those.Thank youu!

Chemistry
1 answer:
xz_007 [3.2K]2 years ago
5 0

Answer:

2,3-dimethylpentanal

3,4-heptadienal

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a piece of candy is burned in a calorimeter raising up the tempature of 500g of water from 21 C to 25 C water has a specific hea
OverLord2011 [107]
   The energy  that was  released   by the candy  is calculates using the below formula
Q=Mc delta T

Q= heat energy
m= mass (500g)
C= specific heat  capacity) = 4.18 j/g/c
 delta t =change in temperature = 25- 21 = 4 c

Q=  500 g  x 4.18 j/g/c x 4c = 8360  j

3 0
3 years ago
4. What is the total mass of ice that can be vaporized by 2100 kJ of heat energy?
anygoal [31]

Answer:

5 g

Explanation:

The heat required to vaporize ice is the sum of

i) Heat required to melt ice at 0°C

ii) Heat required to raise the temperature from  0°C to 100°C

iii) Heat required to vaporize water at 100°C

Thus;

H = nLfus + ncθ + nLvap

H= n(Lfus + cθ + Lvap)

Lfus = 6.01 kJ/mol

Lvap = 41 kJ/mol

c = 75.38

n =?

2100 = n(6.01  + 75.38(100) + 41)

n = 2100 KJ/7585.01 kJ/mol

n = 0.277 moles

Mass of water = number of moles * molar mass

Mass of water = 0.277 moles * 18 g/mol

Mass of water =  5 g

3 0
3 years ago
Calculate the pressure (in kpa) of 1.5 mole of helium gas at 354 k when it occupies a volume of 16.5l.
3241004551 [841]

Answer:

267.57 kPa

Explanation:

Ideal gas law:

PV = n RT        R = 8.314462    L-kPa/K-mol

P (16.5) = 1.5 (8.314462)(354)       P = 267.57 kPa

8 0
2 years ago
I'll give brainliest
ss7ja [257]

Answer:

b,d,f

Explanation:your welcome give brainilest

8 0
2 years ago
Read 2 more answers
The atomic symbol Superscript 206 subscript 82 upper P b. represents lead-206 (Pb-206), an isotope that has 82 protons and 124 n
Serggg [28]

Answer:

\left \{ {{y=206} \atop {x=82}}Pb \right.

Explanation:

isotopes are various forms of same elements with different atomic number but different mass number.

Radioactivity is the emission of rays or particles from an atom to produce a new nuclei. There are various forms of radioactive emissions which are

  • Alpha particle emission  \left \{ {{y=4} \atop {x=2}}He \right.
  • Beta particle emission    \left \{ {{y=0} \atop {x=-1}}e \right.
  • gamma radiation             \left \{ {{y=0} \atop {x=0}}γ \right.

in the problem the product formed after radiation was Pb-206. isotopes of lead include Pb-204, Pb-206, Pb-207, Pb-208. they all have atomic number 82. which means the radiation cannot be ∝ or β since both radiations will alter the atomic number of the parent nucleus.

Only gamma radiation with \left \{ {{y=0} \atop {x=0}}γ \right. will produce a Pb-206 of atomic number 82 and mass number 206 , since gamma ray have 0 mass and has 0 atomic number.equation is shown below

\left \{ {{y=206} \atop {x=82}}Pb\right ⇒ \left \{ {{y=206} \atop {x=82}}Pb\right +  \left \{ {{y=0} \atop {x=0}}γ\right.

Thus the atomic symbol is \left \{ {{y=206} \atop {x=82}}Pb\right

8 0
3 years ago
Read 2 more answers
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