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Anarel [89]
3 years ago
8

Consider the condensed structure shown.

Chemistry
1 answer:
neonofarm [45]3 years ago
7 0

Answer:

C_{5}H_{10}\:C_{2}H_{6}

Explanation:

Expanded Structure shows all the atoms and the bonds of the molecule. It is important to remember, each Carbon molecule have four bonds, while the Hydrogen just one. So:

1)C_{5}H_{10}

Pentene. 5 Carbon molecules, 10 Hydrogen molecules. It's an isomer, so this organic compound has multiple arrangements.

2) C_{2}H_{6}

Ethane. 2 Carbon and 6 Hydrogen Molecules. Check it below.

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Why air is classified as a mixture​
Vika [28.1K]

Answer:

See explanation

Explanation:

Air contains a mixture of several molecules and compounds such as oxygen and carbon dioxide.

5 0
2 years ago
The dissociation of sulfurous acid (H2SO3) in aqueous solution occurs as follows:
aksik [14]

Answer:

The [SO₃²⁻]

Explanation:

From the first dissociation of sulfurous acid we have:

                         H₂SO₃(aq) ⇄ H⁺(aq) + HSO₃⁻(aq)

At equilibrium:  0.50M - x          x            x

The equilibrium constant (Ka₁) is:

K_{a1} = \frac{[H^{+}] [HSO_{3}^{-}]}{[H_{2}SO_{3}]} = \frac{x\cdot x}{0.5 - x} = \frac {x^{2}}{0.5 -x}

With Ka₁= 1.5x10⁻² and solving the quadratic equation, we get the following HSO₃⁻ and H⁺ concentrations:

[HSO_{3}^{-}] = [H^{+}] = 7.94 \cdot 10^{-2}M

Similarly, from the second dissociation of sulfurous acid we have:

                              HSO₃⁻(aq) ⇄ H⁺(aq) + SO₃²⁻(aq)

At equilibrium:  7.94x10⁻²M - x          x            x

The equilibrium constant (Ka₂) is:  

K_{a2} = \frac{[H^{+}] [SO_{3}^{2-}]}{[HSO_{3}^{-}]} = \frac{x^{2}}{7.94 \cdot 10^{-2} - x}  

Using Ka₂= 6.3x10⁻⁸ and solving the quadratic equation, we get the following SO₃⁻ and H⁺ concentrations:

[SO_{3}^{2-}] = [H^{+}] = 7.07 \cdot 10^{-5}M

Therefore, the final concentrations are:

[H₂SO₃] = 0.5M - 7.94x10⁻²M = 0.42M

[HSO₃⁻] = 7.94x10⁻²M - 7.07x10⁻⁵M = 7.93x10⁻²M

[SO₃²⁻] = 7.07x10⁻⁵M

[H⁺] = 7.94x10⁻²M + 7.07x10⁻⁵M = 7.95x10⁻²M

So, the lowest concentration at equilibrium is [SO₃²⁻] = 7.07x10⁻⁵M.

I hope it helps you!

8 0
3 years ago
The solubility KI is 50 g in 100 g of H2O at 20 °C. if 110 grams of ki are added to 200 grams of H2O ________
Salsk061 [2.6K]

The solubility KI is 50 g in 100 g of H₂O at 20 °C. if 110 grams of ki are added to 200 grams of H₂O <u>the </u><u>solution </u><u>will be </u><u>saturated</u><u>.</u>

<h3>What is solubility?</h3>

Solubility is a condition where the solute is fully dissolved in the solvent. When fully mixed with the solvent.

Given that 50 g of KI is added to 100 g of water at 20 °C it means 100 g of water can dissolve a maximum of 50 g of  KCl.

1 g of water will dissolve an quantity of 0.5 g of  KCl.

To assay for 200 g of water: 200 g of water can disintegrate a maximum of (0.5) x 200 g of  KCl.

The maximum amount of KCl that will dissolve is 100 g

Actualised amount dissolved = 110 g

when Amount dissolved > Maximum solubility limit

110 g > 100 g

Thus,  the solution is saturated.

To learn more about solubility, refer to the below link:

brainly.com/question/8591226

#SPJ4

6 0
1 year ago
What element is being oxidized in the following redox reaction?
GrogVix [38]

Answer:

The O is being oxidized, but at the same time, is being reducted.

Explanation:

H₂O₂(l) + ClO₂(aq) → ClO₂(aq) + O₂(g)

In this reaction, we have 4 compounds:

Hydrogen peroxide

Chlorine dioxide (twice)

Oxygen

In both dioxide, the Cl acts with +4 in oxidation state; the oxygen acts with -2.

Oxgen in ground state has 0, as oxidation number.

In peroxide, the H acts with +1 but  the oxygen acts with -1.

Peroxide is making the oxidation number from the O in the ClO₂, to decrease (reduction) and to increase in the O, at the ground state.

Hydrogen peroxide is a good reducing and oxidizing agent at the same time.

4 0
3 years ago
Which of the two forces is greater the force on the firefly or the force on the bus explain your answer please I really need hel
maksim [4K]

Answer: The force on the firefly

The unfortunate firefly hitting the bus does not change the velocity of the bus very much. Technically there is a change, but it's so very small and miniscule that it barely registers. To any casual observer not paying very close attention, they don't notice anything at all. So effectively the force on the firefly is a lot greater since the firefly got the worst end of the deal.

So in short, we look at the velocity of each object and see which velocity changed the most. In this case, the firefly's velocity changed from whatever speed it was flying to 0 when it stops flying all together. That's why the force is greater on the bug.

8 0
2 years ago
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