Carbon Dioxide environmental gas so as to make carbonic corrosive that is consolidated with water. Carbon dioxide noticeable all around can disintegrate in rain water to frame carbonic corrosive, H2CO3. Carbonic corrosive is a powerless corrosive. It somewhat ionizes to frame hydrogen particles. The hydrogen particles from carbonic corrosive give common rain water a somewhat corrosive pH estimation of 5.6.
Yes your choices of B C D are right
Answer:
They are:
H2, N2, O2, F2, Cl2, Br2, and I2.
Note: whether the element At molecule is monoatomic or diatomic is incredibly arguable. While some say it exists as diatomic because it is a halogen like bromine, iodine etc, At is in fact extremely unstable and no one has ever really studied the molecules on it, so, when others say it is monoatomic, this is also based on calculations. But the other 7 elements listen above is for sure diatomic.
Answer: Enthalpy of combustion (per mole) of
is -2657.5 kJ
Explanation:
The chemical equation for the combustion of butane follows:

The equation for the enthalpy change of the above reaction is:
![\Delta H^o_{rxn}=[(8\times \Delta H^o_f_{CO_2(g)})+(10\times \Delta H^o_f_{H_2O(g)})]-[(1\times \Delta H^o_f_{C_4H_{10}(g)})+(4\times \Delta H^o_f_{O_2(g)})]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%288%5Ctimes%20%5CDelta%20H%5Eo_f_%7BCO_2%28g%29%7D%29%2B%2810%5Ctimes%20%5CDelta%20H%5Eo_f_%7BH_2O%28g%29%7D%29%5D-%5B%281%5Ctimes%20%5CDelta%20H%5Eo_f_%7BC_4H_%7B10%7D%28g%29%7D%29%2B%284%5Ctimes%20%5CDelta%20H%5Eo_f_%7BO_2%28g%29%7D%29%5D)
We are given:

Putting values in above equation, we get:
![\Delta H^o_{rxn}=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.6)+(4\times 0)]\\\\\Delta H^o_{rxn}=-5315kJ](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%288%5Ctimes%20-393.5%29%2B%2810%5Ctimes%20-241.82%29%5D-%5B%282%5Ctimes%20-125.6%29%2B%284%5Ctimes%200%29%5D%5C%5C%5C%5C%5CDelta%20H%5Eo_%7Brxn%7D%3D-5315kJ)
Enthalpy of combustion (per mole) of
is -2657.5 kJ
Answer:
mole fraction of N_2 O = 0.330
mole of fraction SF_4 = 0.669
PRESSURE OF N_2 O = 39127.053 Pa
pressure of SF_4 = 792126.36
Total pressure = 118253.413 Pa
Explanation:
Given data:
volume of tank 8 L
Weight of dinitrogen difluoride gas 5.53 g
weight of sulphur hexafluoride gas 17.3 g
Amount of 
amount of 
mole fraction of 
mole of fraction
PV = nRT
P of N_2 O 
mole of SF_4
Total pressure = 39127.053 + 79126.36 = 118253.413 Pa