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Volgvan
2 years ago
13

Why do real gases not behave exactly like ideal gases?

Chemistry
2 answers:
Korvikt [17]2 years ago
5 0

The theory assumes that collisions between gas molecules and the walls of a container are perfectly elastic, gas particles do not have any volume, and there are no repulsive or attractive forces between molecules .

BigorU [14]2 years ago
4 0

At high pressure and low temperature, real gas deviates from ideal gas. Compressibility factor is used to measure the deviation of real gas from ideal gas.

The compressibility factor is "n" which equals PV/RT.This is equal to one in case of ideal gas and this condition does not hold good for real gas.


At high pressures, the molecules in the gas tend to become closer, resulting in greater intermolecular forces. Internal molecular force holds these molecules together,prevents movement and collision and thus reduces the pressure of the gas much below than that of an ideal gas.


At low temperatures, the kinetic energy of the gas molecules also becomes less thus this results in less collision of the gas molecules and thus finally this results in the decrease in pressure of the gas molecules which would be much lower than that of an ideal gas.


For an ideal gas, the translational kinetic energy is 3/2kT. This condition does not hold good for a real gas.

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<em />

To reach the end point in this titration, we need to add the same moles of Ba²⁺ that the moles that are of SO₄²⁻.

Thus, to find molarity of SO₄²⁻ we need to find first the moles of Ba²⁺ added (That will be the same of SO₄²⁻). And as the volume of the initial sample was 100mL we can find molarity (As ratio of moles of SO₄²⁻ per liter of solution).

<em>Moles Ba²⁺:</em>

7.48mL = 7.48x10⁻³L ₓ (0.0250moles / L) = 1.87x10⁻⁴ moles of Ba²⁺ = Moles of SO₄²⁻

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As there are 1.87x10⁻⁴ moles of SO₄²⁻ in 100mL = 0.1L, molarity is:

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