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agasfer [191]
3 years ago
8

Its due tomorrow need help!!

Mathematics
1 answer:
IrinaVladis [17]3 years ago
6 0

Let s represent the measure of the second angle.

The measure of the first angle is 15° less than the second, so we can represent the first angle by (s-15).

The measure of the third angle is 45° more than half the second, so we can represent the third angle by (45+(s/2)).

The sum of these angles is 180°, so we can represent the sum as

... (s-15) + s + (45+s/2) = 180

Collecting terms, we have

... 2.5s +30 = 180

... 2.5s = 150 . . . . . . subtract 30

... s = 150/2.5 = 60 . . . . divide by the coefficient of s

The first angle is 60-15 = 45.

The second angle is 60.

The third angle is 45+60/2 = 75.

_____

<u>Check</u>

The sum of the three angles is 45 +60 +75 = 180.

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Subtract the sum of (13x - 4y + 7z) and (- 6z + 6x + 3y) from the sum of (6x - 4y - 4z) and (2x + 4y - 7z).

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