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Olenka [21]
3 years ago
14

Which option identifies the most likely scaling factor in the above drawing of the Mercury capsule and booster unit? 1:1,000 1:1

0,000 1,000:1 10,000:1
Engineering
1 answer:
Elina [12.6K]3 years ago
3 0

Answer:

I would say 10000;1 but thats just me

Explanation:

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Why excess air is required to burn a fuel completely
8_murik_8 [283]

Explanation:

excess air is required to ensure adequate mixing of fuel and air, avoid smoke, minimize sg in Coal burning, and to ensure maximum steam output.

5 0
3 years ago
Read 2 more answers
Assume a steel pipe of inner radius r1= 20 mm and outer radius r2= 25 mm, which is exposed to natural convection at h = 50 W/m2.
Mekhanik [1.2K]

Answer:

98,614.82 W/m²

Explanation:

Q = 2\pi hL(\frac{T_2-T_1}{Ln\frac{r_2}{r_1}})

Where;

Q = the amount of heat loss from the pipe

h =  the heat transfer coefficient of the pipe = 50 W/m².K

T₁ = the ambient temperature of the pipe = 30⁰C

T₂  = the outside temperature of the pipe = 100⁰C

L= the length of pipe

r₁ = inner radius of the pipe = 20mm

r₂ = outer radius of the pipe = 25mm

To determine the amount of heat loss from the pipe per unit length

From the equation above

\frac{Q}{L} = 2\pi h(\frac{T_2-T_1}{Ln\frac{r_2}{r_1}})

\frac{Q}{L} = 2\pi* 50(\frac{100-30}{Ln\frac{25}{20}})

\frac{Q}{L} = 314.159(\frac{70}{0.223})

\frac{Q}{L} = 314.159(313.901) = 98,614.82 W/m²

3 0
3 years ago
A gas mixture containing 3 moles CO2, 5 moles H2 and 1 mole water is undergoing the following reactions CO2+3H2 →cH3OH + H2O Dev
Ilya [14]
Aaaaaaaaaaaaaaaaaaaaaa
7 0
2 years ago
A steel bar 110 mm long and having a square cross section 22 mm on an edge is pulled in tension with a load of 89,000 N, and exp
iragen [17]

Answer:

Elastic modulus of steel  = 202.27 GPa

Explanation:

given data

long = 110 mm = 0.11 m

cross section 22 mm  = 0.022 m

load = 89,000 N

elongation = 0.10 mm = 1 × 10^{-4} m

solution

we know that Elastic modulus is express as

Elastic modulus = \frac{stress}{strain}    ................1

here stress is

Stress = \frac{Force}{area}       .................2

Area = (0.022)²

and  

Strain = \frac{extension}{length}       .............3

so here put value in equation 1 we get

Elastic modulus = \frac{89,000\times 0.11}{0.022^2 \times 1 \times 10^{-4} }  

Elastic modulus of steel = 202.27 × 10^9 Pa

Elastic modulus of steel  = 202.27 GPa

3 0
3 years ago
What are the Basic requirements of drinking Water ?
iragen [17]

Answer:

1) free of contaminants, 2) alkaline, and 3) micro-clustered

Explanation:

Hope it helps you

4 0
2 years ago
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