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love history [14]
3 years ago
15

Find the value of x that will make a || B

Mathematics
1 answer:
belka [17]3 years ago
4 0

Answer:

x = 30

Step-by-step explanation:

4x + 2x = 180

6x = 180  

x = 30

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The expression 28 + 63 is equivalent to<br> 1 91<br> 2 5,7<br> 3 6/7<br> 4 13,7
Yuliya22 [10]

Answer:

1) 91

Step-by-step explanation:

28 + 63 = 91

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3 years ago
Solve this equation <br> ÷2(1+2)
nasty-shy [4]
The answer is 6 because you add the 1 and the 2 first and then multiple to get 6. I don’t know why you put the division sign in front of the 2 though.
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3 years ago
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The are 66 small wooden animals to sell at the craft fair . He displays in rows of 7 animals in a row. How many will not be in a
lord [1]

Answer:

9

Step-by-step explanation:

There would be 9 because 7 goes into 66 9 times

4 0
3 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
4 years ago
4 ten thousands eight hundreds ÷ 10
MariettaO [177]
40,000 divided by 10 is 4,000
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