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3 years ago

4(x-6)²-3=97 what is the highest and lowest answer

Mathematics

1 answer:

lapo4ka [179]3 years ago

5 0

Answer:

x=1

x=11

Step-by-step explanation:

4(x-6)²-3=97

Add 3 to each side

4(x-6)²-3+3=97+3

4(x-6)²=100

Divide each side by 4

4/4(x-6)²=100/4

(x-6)²=25

Take the square root of each side

sqrt(4(x-6)²)=sqrt(25)

x-6 = ±5

Separating into two equations

x-6 = 5 x-6 = -5

Add 6 to each side

x-6+6 = 5+6 x-6+6 = -5+6

x=11 x=1

The two solutions are 1, 11

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3 years ago

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4 years ago

Here are two squares A and B. The length of the side A is 50% of the length of the side square B. Express the area of the shaded

Darya [45]

Answer:

12.5%

Step-by-step Explanation:

==>Given:

Square A side length = 50% Square B side length

Area of Square A that is shaded = ½ of the area of Square B

==>Required:

Area of shaded region of Square A as a % of Area of Square B

==>Solution:

Let "b" be the side length of Square B

Let "a" be the side length of Square A

Since we are told that the side length of Square A (a) = 50% of side length of Square B (b), thus we have,

a = ½b

==>Let's find the area of Square A and Square B:

Area of a square = s², where s = side length

Area of Square A = (½b)² = b²/4

Area of Square B = b²

==>Let's find the area of the shaded region of the Square A = ½ of area of Square A.

Thus,

Area of shaded region of Square A = ½*(b²/4) = b²/8

==>Let's express the area of the shaded portion of square A as a percentage of are of Square B:

Thus, Area of shaded portion of Square A ÷ Area of Square B × 100%

$= \frac{\frac{b^{2} }{8} }{b^{2} } * 100$

$= \frac{b^{2} }{8} * \frac{1}{b^{2} } * 100$

$= \frac{b^{2}*1 }{8*b^{2} } * 100$

$= \frac{b^{2} }{8*b^{2} } * 100$

$= \frac{1}{8} * 100 = 12.5$

The area of the shaded region of Square A is 12.5% of the area of Square B.

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3 years ago