Question

In Exercise, find the derivative of the function. y = 32e0.23t

Answer 1

Answer:

$y'=7.36e^{0.23t}$

Step-by-step explanation:

$y=32e^{0.23t}$

take derivative with respect to t

$\frac{dy}{dt} =32\frac{d(e^{0.23t})}{dt}$

derivative of e^t is e^t

derivative of 0.23t is 0.23

$\frac{dy}{dt} =32 \frac{d(e^{0.23t})}{dt}$

Apply chain rule

$\frac{dy}{dt} =32(e^{0.23t})(0.23)$

$y'=7.36e^{0.23t}$