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nikdorinn [45]
3 years ago
11

How to isolate scalars from a matrix

Mathematics
1 answer:
I am Lyosha [343]3 years ago
3 0
The technique of matrix isolation involves condensing the substance to be studied with a large excess of inert gas (usually argon or nitrogen) at low temperature to form a rigid solid (the matrix). The early development of matrix isolation spectroscopy was directed primarily to the study of unstable molecules and free radicals. The ability to stabilise reactive species by trapping them in a rigid cage, thus inhibiting intermolecular interaction, is an important feature of matrix isolation. The low temperatures (typically 4-20K) also prevent the occurrence of any process with an activation energy of more than a few kJ mol-1. Apart from the stabilisation of reactive species, matrix isolation affords a number of advantages over more conventional spectroscopic techniques. The isolation of monomelic solute molecules in an inert environment reduces intermolecular interactions, resulting in a sharpening of the solute absorption compared with other condensed phases. The effect is, of course, particularly dramatic for substances that engage in hydrogen bonding. Although the technique was developed to inhibit intermolecular interactions, it has also proved of great value in studying these interactions in molecular complexes formed in matrices at higher concentrations than those required for true isolation.
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A Japanese garden has a circular koi pond in the middle that has a radius of 3 feet. A rectangle with length of 16 feet and widt
Mariulka [41]

Answer:

first, find the area of the circle cut.

r= 3 feet

π=3.14

area of a circle= πr²= 3.14×3×3= 28.26 sq.feet

Now, find the area of the rectangle and subtract it by the area of the circle.

area of rectangle = l×b

length of the rectangle= 16 feet

breadth/width of the rectangular garden= 14 feet

area=  16×14= 224 sq. feet

now, area of the garden surrounding the koi pond=  224-28.26

                                                                                     =195.74 sq. feet

7 0
3 years ago
Can you help me with this Q i cant get it i have 3 min only please help me :)
Butoxors [25]

x= 3

AC = 22

hope it helps you...

7 0
2 years ago
What is the y-value of the solution to the system of equations?
alukav5142 [94]

Let's solve for x first,


3x + 5y - 5y = 1 - 5y

3x/3 = 1/3 - 5y/3

x = 1/3 - 5/3y


Let's now plug that into the other equation,


7(1/3 - 5/3y) + 4y = -13

7/3 - 35/3y + 4y = -13

7/3 - 7 2/3y - 7/3 = -13 - 7/3

- 7 2/3y (-3/23) = -15 1/3 (-3/23)

y = 2



The answer is 2

4 0
3 years ago
The sum of the squares of two consecutive positive integers is 41. Find the two
Komok [63]

We have to present the number 41 as the sum of two squares of consecutive positive integers.

1² = 1

2² = 4

3² = 9

4² = 16

5² = 25

16 + 25 = 41

<h3>Answer: 4 and 5</h3>

Other method:

n, n + 1 - two consecutive positive integers

The equation:

n² + (n + 1)² = 41     <em>use (a + b)² = a² + 2ab + b²</em>

n² + n² + 2(n)(1) + 1² = 41

2n² + 2n + 1 = 41     <em>subtract 41 from both sides</em>

2n² + 2n - 40 = 0     <em>divide both sides by 2</em>

n² + n - 20 = 0

n² + 5n - 4n - 20= 0

n(n + 5) - 4(n + 5) = 0

(n + 5)(n - 4) = 0 ↔ n + 5 = 0 ∨ n - 4 =0

n = -5 < 0 ∨ n = 4 >0

n = 4

n + 1 = 4 + 1 = 5

<h3>Answer: 4 and 5.</h3>
7 0
3 years ago
IM DOING A GIVE AWAY OF 100 POINTS
Goryan [66]
Happy birthday kiddo?!
4 0
3 years ago
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