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nikdorinn [45]
3 years ago
11

How to isolate scalars from a matrix

Mathematics
1 answer:
I am Lyosha [343]3 years ago
3 0
The technique of matrix isolation involves condensing the substance to be studied with a large excess of inert gas (usually argon or nitrogen) at low temperature to form a rigid solid (the matrix). The early development of matrix isolation spectroscopy was directed primarily to the study of unstable molecules and free radicals. The ability to stabilise reactive species by trapping them in a rigid cage, thus inhibiting intermolecular interaction, is an important feature of matrix isolation. The low temperatures (typically 4-20K) also prevent the occurrence of any process with an activation energy of more than a few kJ mol-1. Apart from the stabilisation of reactive species, matrix isolation affords a number of advantages over more conventional spectroscopic techniques. The isolation of monomelic solute molecules in an inert environment reduces intermolecular interactions, resulting in a sharpening of the solute absorption compared with other condensed phases. The effect is, of course, particularly dramatic for substances that engage in hydrogen bonding. Although the technique was developed to inhibit intermolecular interactions, it has also proved of great value in studying these interactions in molecular complexes formed in matrices at higher concentrations than those required for true isolation.
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g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa
adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is  \sigma =  0.0133

Step-by-step explanation:

From the question we are told that

   The upper specification is  USL  =  1.68 \ mm

    The lower specification is  LSL  = 1.52  \  mm

     The sample mean is  \mu =  1.6 \  mm

     The standard deviation is  \sigma =  0.03 \ mm

Generally the capability index in mathematically represented as

             Cpk  =  min[ \frac{USL -  \mu }{ 3 *  \sigma }  ,  \frac{\mu - LSL }{ 3 *  \sigma } ]

Now what min means is that the value of  CPk is the minimum between the value is the bracket

          substituting value given in the question

           Cpk  =  min[ \frac{1.68 -  1.6 }{ 3 *  0.03 }  ,  \frac{1.60 -  1.52 }{ 3 *  0.03} ]

=>      Cpk  =  min[ 0.88 , 0.88  ]

So

         Cpk  = 0.88

Now from the question we are asked to evaluated the value of  standard deviation that will produce a  capability index of 2

Now let assuming that

         \frac{\mu - LSL  }{ 3 *  \sigma } =  2

So

         \frac{ 1.60 -  1.52  }{ 3 *  \sigma } =  2

=>    0.08 = 6 \sigma

=>     \sigma =  0.0133

So

        \frac{ 1.68  - 1.60 }{ 3 *  0.0133 }

=>      2

Hence

      Cpk  =  min[ 2, 2 ]

So

    Cpk  = 2

So    \sigma =  0.0133 is  the value of standard deviation required

3 0
3 years ago
What are the like terms in this expression?<br><br> 9a - 3b + 4ab
sergey [27]
There are no like terms
6 0
3 years ago
Use the Central Limit Theorem to find a mean given a probability Question A video game company sells an average of 132 games a m
aev [14]

Answer:

The number of games must a store sell in order to be eligible for a reward is 135.

Step-by-step explanation:

Let the random variable <em>X</em> represent the number of video games sold in a month by the sores.

The random variable <em>X</em> has a mean of, <em>μ</em> = 132 and a standard deviation of, <em>σ</em> = 9.

It is provided that the company is looking to reward stores that are selling in the top 7%.

That is, P (\bar X > \bar x) = 0.07.

The <em>z</em>-score related to this probability is, <em>z</em> = 1.48.

Compute the number of games must a store sell in order to be eligible for a reward as follows:

z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}

\bar x=\mu+z\cdot \sigma/\sqrt{n}

   =132+1.48\times (9/\sqrt{36})\\\\=132+2.22\\\\=134.22\\\\\approx 135

Thus, the number of games must a store sell in order to be eligible for a reward is 135.

5 0
3 years ago
The tree diagram below shows all of the possible outcomes for flipping three coins.
Pepsi [2]

Answer:

5

Step-by-step explanation:

Ghhjj fun in jjhv GUI gh

3 0
3 years ago
Evaluate the expression for x = 3 y= 1/3 and z= 5. 12 x - 3y over 4 x - Z​
Zepler [3.9K]

Answer:

35.786

12(3) - 3(1/2)/4(3) - 5

This is then further simplified to:

36 - 1.5/7

And when you divide 1.5 by 7, the number (rounded) is .214.

Thus, subtract, and gain the final answer of 35.786.

Hope this helps!

Step-by-step explanation:

Can you please mark me brainliest

6 0
3 years ago
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