Answer:
first, find the area of the circle cut.
r= 3 feet
π=3.14
area of a circle= πr²= 3.14×3×3= 28.26 sq.feet
Now, find the area of the rectangle and subtract it by the area of the circle.
area of rectangle = l×b
length of the rectangle= 16 feet
breadth/width of the rectangular garden= 14 feet
area= 16×14= 224 sq. feet
now, area of the garden surrounding the koi pond= 224-28.26
=195.74 sq. feet
Let's solve for x first,
3x + 5y - 5y = 1 - 5y
3x/3 = 1/3 - 5y/3
x = 1/3 - 5/3y
Let's now plug that into the other equation,
7(1/3 - 5/3y) + 4y = -13
7/3 - 35/3y + 4y = -13
7/3 - 7 2/3y - 7/3 = -13 - 7/3
- 7 2/3y (-3/23) = -15 1/3 (-3/23)
y = 2
The answer is 2
We have to present the number 41 as the sum of two squares of consecutive positive integers.
1² = 1
2² = 4
3² = 9
4² = 16
5² = 25
16 + 25 = 41
<h3>Answer: 4 and 5</h3>
Other method:
n, n + 1 - two consecutive positive integers
The equation:
n² + (n + 1)² = 41 <em>use (a + b)² = a² + 2ab + b²</em>
n² + n² + 2(n)(1) + 1² = 41
2n² + 2n + 1 = 41 <em>subtract 41 from both sides</em>
2n² + 2n - 40 = 0 <em>divide both sides by 2</em>
n² + n - 20 = 0
n² + 5n - 4n - 20= 0
n(n + 5) - 4(n + 5) = 0
(n + 5)(n - 4) = 0 ↔ n + 5 = 0 ∨ n - 4 =0
n = -5 < 0 ∨ n = 4 >0
n = 4
n + 1 = 4 + 1 = 5
<h3>Answer: 4 and 5.</h3>