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podryga [215]
2 years ago
15

Mr. Phillips' car is parked on a steep hill with the brakes applied and the engine off. Because of the car's position, it has gr

avitational potential energy. How could this gravitational potential energy be transformed into kinetic energy?
A. He could push it up the hill.


B. He could release the brakes.


C. He could start the engine.


D. all of these
Physics
1 answer:
aivan3 [116]2 years ago
4 0

Answer:

The anser is b

Explanation:

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Yes, It has a stored energy in that stone.
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3 years ago
A 3.3 kg ball sits on the ground and is kicked with a FAPP of 36N
jeyben [28]

a) 32.3 N

The force of gravity (also called weight) on an object is given by

W = mg

where

m is the mass of the object

g is the acceleration of gravity

For the ball in the problem,

m = 3.3 kg

g = 9.8 m/s^2

Substituting, we find the force of gravity on the ball:

W=(3.3)(9.8)=32.3 N

b) 48.3 N

The force applied

F_{app} = 36 N

The ball is kicked with this force, so we can assume that the kick is horizontal.

This means that the applied force and the weight are perpendicular to each other. Therefore, we can find the net force by using Pythagorean's theorem:

F=\sqrt{W^2+F_{app}^2}

And substituting

W = 32.3 N

Fapp = 36 N

We find

F=\sqrt{32.3^2+36^2}=48.3 N

c) 14.6 m/s^2

The ball's acceleration can be found by using Newton's second law, which states that

F = ma

where

F is the net force on an object

m is its mass

a is its acceleration

For the ball in this problem,

m = 3.3 kg

F = 48.3 N

Solving the equation for a, we find

a=\frac{F}{m}=\frac{48.3}{3.3}=14.6 m/s^2

8 0
3 years ago
Two important economic activities in Norden are _____.
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Fishing and Agriculture.
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3 years ago
Read 2 more answers
A 2000 kg truck traveling north at 34 km/h turns east and accelerates to 58 km/h. (a) What is the change in the truck's kinetic
barxatty [35]

Explanation:

It is given that,

Mass of the truck, m = 2000 kg

Initial velocity of the truck, u = 34 km/h = 9.44 m/s

Final velocity of the truck, v = 58 km/h = 16.11 m/s

(a) Change in truck's kinetic energy, \Delta E=\dfrac{1}{2}m(v^2-u^2)

\Delta E=\dfrac{1}{2}\times 2000\ kg\times (16.11^2-9.44^2)

\Delta E=170418.5\ J

\Delta E=1.7\times 10^5\ J

(b) Change in momentum of the truck, \Delta p=m(v-u)

\Delta p=2000\ kg\times (16.11-9.44)

\Delta p=13340\ kg-m/s

Hence, this is the required solution.

6 0
3 years ago
Explain a situation in which you can accelerate even thought your speed doesn’t change
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Explanation:

An object's acceleration is the rate its velocity (speed and direction) changes. Therefore, an object can accelerate even if its speed is constant - if its direction changes. ... Light's acceleration is zero. Since it travels in a straight line, its direction does not change.

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