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Nitella [24]
2 years ago
8

Grouping data in a report will (Points : 4) provide grand totals for your report.

Computers and Technology
1 answer:
zaharov [31]2 years ago
3 0

Answer: Let you organize and summarize your data.

Explanation: Data grouping is referred as the making a collection or cluster of data in a report .The group is made for the summarization of the information and makes easily understandable according to the subject or field due to the proper organization.

Other given options are incorrect because it does not provide the total of the report content,attractive form of the data or editing function in report.Thus the correct option is summarizing and organizing the data.

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Now, extend your test program by adding a second function named split that will identify all the individual values in a comma se
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Answer:

The code to copy is :

#include <iostream>

#include <string>

using namespace std;

string nextString(string str, int start_index);

int split(string str, string a[], int max_size);

int main()

{

const int VALUES = 20;

string somestring;

string varray[VALUES];

//Prompt the user to enter a comma separated string

cout << "Enter a comma seperated string: ";

//read the string

getline(cin, somestring);

//call split() method on the given string and

//store the count of individual strings in cnt

int cnt = split(somestring, varray, VALUES);

//Print the individual strings

for (int i = 0; i<cnt; i++)

cout << varray[i] << endl;

return 0;

}

//returns a sub string that starts at strat_index

//in the given string and ends before a comma

string nextString(string str, int start_index)

{

int i;

//find a comma or end of the string, after strat_index

for (i = start_index;i < str.length();i++)

{

//if comma is found, exit the loop

if (str.at(i) == ',')

break;

}

//extract the sub string

string out= str.substr(start_index, i-start_index);

return out;

}

//splits the comma separted string as individual strings

//and returns the number of individual strings

int split(string str, string a[], int max_size)

{

int i, j;

int start_index = 0;

//search for commas in the given string

for (i = 0,j=0;i < str.length();i++)

{

//if comma is identified or end of the string is identified

//, then get a strig that starts at start_index using next string

if (str.at(i) == ',' ||i==str.length()-1)

{

//save each string into an array of strings

a[j] = nextString(str, start_index);

//update the next string starting postion(starts after comma)

start_index = i + 1;

j++;

}

}

return j;

Explanation:

Please see attachments

7 0
3 years ago
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